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3 years ago

........................

Mathematics

2 answers:

omeli [17]3 years ago

5 0

it would be C i think hope this helps

Vitek1552 [10]3 years ago

5 0

Answer:

3.78 in

Step-by-step explanation:

Since it's not a full 100%, 84% can be turned into .84.

.84 * 4.5 = 3.78 in

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Required information Skip to question A die (six faces) has the number 1 painted on two of its faces, the number 2 painted on th

grigory [225]

Answer:

The change to the face 3 affects the value of P(Odd Number)

Step-by-step explanation:

Analysing the question one statement at a time.

Before the face with 3 is loaded to be twice likely to come up.

The sample space is:

$S = \{1,1,2,2,2,3\}$

And the probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{6}$

$P(1) = \frac{1}{3}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{6}$

$P(2) = \frac{1}{2}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{6}$

P(Odd Number) is then calculated as:

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{1}{3} + \frac{1}{6}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{6}$

$P(Odd\ Number) = \frac{3}{6}$

$P(Odd\ Number) = \frac{1}{2}$

After the face with 3 is loaded to be twice likely to come up.

The sample space becomes:

$S = \{1,1,2,2,2,3,3\}$

The probability of each is:

$P(1) = \frac{n(1)}{n(s)}$

$P(1) = \frac{2}{7}$

$P(2) = \frac{n(2)}{n(s)}$

$P(2) = \frac{3}{7}$

$P(3) = \frac{n(3)}{n(s)}$

$P(3) = \frac{1}{7}$

$P(Odd\ Number) = P(1) + P(3)$

$P(Odd\ Number) = \frac{2}{7} + \frac{1}{7}$

Take LCM

$P(Odd\ Number) = \frac{2+1}{7}$

$P(Odd\ Number) = \frac{3}{7}$

Comparing P(Odd Number) before and after

$P(Odd\ Number) = \frac{1}{2}$ --- Before

$P(Odd\ Number) = \frac{3}{7}$ --- After

<em>We can conclude that the change to the face 3 affects the value of P(Odd Number)</em>

7 0

3 years ago

Yuuma applied the steps below to find the product of (–10.2)(–16.4).

goblinko [34]

Answer:

164+3.28

Step-by-step explanation:

(16.4)(10)+(16.4)(0.2)

164+3.28

167.28

4 0

2 years ago

Solve 5u– 5(1–u)=u+8

Alekssandra [29.7K]

Answer:

u= -3

Step-by-step explanation:Solve for

u by simplifying both sides of the equation, then isolating the variable.

6 0

3 years ago

Read 2 more answers

Let u = (1,2), v = (−3,4), and w = (5,0)

sergij07 [2.7K]

Answer:

w-2u-v

Step-by-step explanation:

Given are three vectors u, v and w.

In R^2 we treat first element as x coordinate and 2nd element as y coordinate.

Thus we mark (1,2) in the I quadrant, (-3,4) in II quadrant and (5,0) on positive x axis 5 units form the origin.

b) $w=au+bv$

We have to find the values of a and b

$(5,0) = a(1,2)+b(-3,4)$ ]

Equate the corresponding terms

$5=a-3b\\0=2a+4b$

Divide II equation by 2 to get

$0=a+2b$

Eliminate a

-5 = 5b: b=-1

a=-2

Hence

w = 2u-v

7 0

3 years ago

Determine if the sequence below is arithmetic or

anzhelika [568]

9514 1404 393

Answer:

arithmetic; common difference of 5

Step-by-step explanation:

It usually works well to check differences first. Here, they are ...

8 -3 = 5

13 -8 = 5

These are the same value, so the sequence is arithmetic with a common difference of 5.

7 0

3 years ago