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ioda
3 years ago
13

HELP (SEE IMAGE) what triangle must be a right triangle and why???

Mathematics
2 answers:
pashok25 [27]3 years ago
8 0
The answer would be D
DIA [1.3K]3 years ago
8 0

Answer:

D. \triangle BGC is right angle because $\overleftrightarrow{EG}$⊥ $\overline{CC'}$CC'.

Step-by-step explanation:

Given A figure  in which line EG is perpendicular to Segment CC'

Therfore ,\triangle BGC is a right angled triangle because in which \angle BGC=90^{\circ}

A right angled triangle is that type of triangle in which one angle is of 90 degree .Then ,we say the the triangle is a right angled triangle.

Now , we can see from the given figure  in \triangle BGC line EG is perpendicular is given . Hence, we are given

$\overleftrightarrow{EG}$\perp$\overline {CC}'$

\therefore , \angle BGC=90^{\circ}

Hence, we can say the triangle BGC is a right triangle.

Now, we check given option

A. It is false. Because no information about the triangle A'B'C' .In given statement the triangle A'B'C' is the reflect image of the triangle ABC .So we can not say \triangle A'B'C' is a right angle .

B. ADC is a right triangle because $\overline{AA'}  intersect AC at C.

It is false.Because  we can see from given the figure AC not meet in given figure.

C. \triangle BCC' is a right triangel  because B lies of the reflection .It is false.Because we can't say that BCC' is a right angle if B lies of the reflection.

D. \triangle BGC is a right triangle  because $\overleftrightarrow{EG}\perp$\overline{CC'}

It is true.  Because EG is perpendicular it means \angle BGC=90^{\circ}. Hence, we can say triangle BGC is right triangle.

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Find the value of r ,so that the line passing through the points 6,2 and 10,r given and has a slope of 2
bonufazy [111]

Answer:

10

Step-by-step explanation:

Slope (m) of two points is expressed as :

m = (y2 - y1) / (x2 - x1)

Given m = 2

the equation becomes;

2 = (r - 2) / (10 - 6)

2 = (r - 2) / 4

cross multiplying becomes ;

2 * 4 = r -  2

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3 years ago
Determine the end behavior of the following monomial functions. (That is, does the function output increase without bound (→[inf
rosijanka [135]

Answer:

a) f(x) = x²

As x→[infinity], f(x)→[infinity]

As x→−[infinity], f(x)→[infinity]

For this function, f(x) increases without bound as the input increases or decreases without bound. The graph of this function would be symmetric about the y-axis.

b) g(x) = x³

As x→[infinity], g(x)→[infinity]

As x→−[infinity], g(x)→-[infinity]

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c) h(x)=−6x³.

As x→[infinity], h(x)→-[infinity]

As x→−[infinity], h(x)→[infinity]

h(x) decreases without bound as the input x increases without bound and increases without bound as input x decreases without bound. The graph of this function would also be symmetric about the origin.

Step-by-step explanation:

Normally, end behaviours predict the nature of the graphs of functions (especially as the values of x become very large, both in the positive and negative sense.

f(x) = x²

As x →[infinity],

f(x) = (∞)² → ∞

f(x) →[infinity]

And as x →−[infinity],

f(x) = (-∞)² → ∞

f(x) →[infinity]

For this function, f(x) increases without bound as the input increases or decreases without bound. The graph of this function would be symmetric about the y-axis.

b) g(x) = x³

As x→[infinity],

g(x) = (∞)³ → ∞

g(x)→[infinity]

As x→−[infinity],

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c) h(x)=−6x³.

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h(x) = -6(∞)³ → -6(∞) → -∞

h(x)→-infinity]

As x→−[infinity],

h(x) = -6(-∞)³ → -6(-∞) → ∞

h(x)→[infinity]

h(x) decreases without bound as the input x increases without bound and increases without bound as input x decreases without bound. The graph of this function would also be symmetric about the origin.

Hope this Helps!!!

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