1. Find the H.C.F. of 4x2y3 and 6xy2z.
Solution:
The H.C.F. of numerical coefficients = The H.C.F. of 4 and 6.
Since, 4 = 2 × 2 = 22 and 6 = 2 × 3 = 21 × 31
Therefore, the H.C.F. of 4 and 6 is 2
Answer: sqrt(58)
Step-by-step explanation:
Answer:
18=b
Step-by-step explanation:
Answer:
Hello fellow brainlian, I am pretty sure the answer is A)
Step-by-step explanation:
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