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2 years ago

Multiple Choice

Mathematics

2 answers:

dexar [7]2 years ago

8 0

The answer is A) 3x2 +15x

mote1985 [20]2 years ago

4 0

Answer:

Step-by-step explanation:

since 8 and 7 have the same variable i can add them both and i will get 15x and then i multiply both constant 3 x 2 and get 6. So the only answer that is fit is A.

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35. For the following exercises, given each set of information, find a linear equation satisfying the conditions, if possible.

Montano1993 [528]

Answer:

The linear equation for the line which passes through the points given as (-2,8) and $(4,6), is written in the point-slope form as $y=-\frac{1}{3} x-\frac{26}{3}$ .

Step-by-step explanation:

A condition is given that a line passes through the points whose coordinates are (-2,8) and (4,6).

It is asked to find the linear equation which satisfies the given condition.

Step 1 of 3

Determine the slope of the line.

The points through which the line passes are given as (-2,8) and (4,6). Next, the formula for the slope is given as,

$m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

Substitute $6 \& 8$ for $y_{2}$ and $y_{1}$ respectively, and 4&-2 for $x_{2}$ and $x_{1}$ respectively in the above formula. Then simplify to get the slope as follows, $m=\frac{6-8}{4-(-2)}$

$\begin{aligned}&m=\frac{-2}{6} \\&m=-\frac{1}{3}\end{aligned}$

Step 2 of 3

Write the linear equation in point-slope form.

A linear equation in point slope form is given as,

$y-y_{1}=m\left(x-x_{1}\right)$

Substitute $-\frac{1}{3}$ for m,-2 for $x_{1}$ , and 8 for $y_{1}$ in the above equation and simplify using the distributive property as follows, $y-8=-\frac{1}{3}(x-(-2))$\\ $y-8=-\frac{1}{3}(x+2)$\\ $y-8=-\frac{1}{3} x-\frac{2}{3}$$

Step 3 of 3

Simplify the equation further.

Add 8 on each side of the equation $y-8=-\frac{1}{3} x-\frac{2}{3}$ , and simplify as follows, $y-8+8=-\frac{1}{3} x-\frac{2}{3}+8$

$y=-\frac{1}{3} x-\frac{2+24}{3}$$\\ $$y=-\frac{1}{3} x-\frac{26}{3}$$

This is the required linear equation.

6 0

1 year ago

Help me anyone please & thank you

viktelen [127]

Answer: i'm pretty sure it's option A

8 0

3 years ago

An equiangular triangle is ___ an acute triangle. <br> Always, sometimes, or never

N76 [4]

Never !!!!!!!!!!!!!!!!!

4 0

3 years ago

Read 2 more answers

Find the 4th term if the sequend in which a1 = 2 and a n+1 = -4a n + 2

pshichka [43]

$a_n_+_1=-4a_n_+_2$

dividing both sides by -4, we get:

$a_n_+_2=- \frac{a_n_+_1}{4}$

this means, each term is its previous term divided by -4.

now we can construct the sequence as follows:

$a_1=2$

$a_2=- \frac{a_1}{4}= - \frac{2}{4}= -\frac{1}{2}$

$a_3=- \frac{a_2}{4} =- \frac{ \frac{1}{2} }{4}=- \frac{1}{8}$

$a_4=- \frac{a_3}{4}=- \frac{ \frac{1}{8} }{4}=- \frac{1}{32}$

Answer: the last term is -1/32

3 0

3 years ago

I need help please help me pu

Luba_88 [7]

Answer:

D: x=12

Step-by-step explanation:

7 0

2 years ago