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storchak [24]
3 years ago
14

Work out the value of 3c-4d when c=5 and d= ½

Mathematics
1 answer:
nikdorinn [45]3 years ago
4 0
3(5) - 4(1/2)
15 - 2 = 13
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Chance wants to wish his cousin a happy birthday at 9:00am CST. Chance lives in Texas and his cousin lives in Ohio. What time wi
Neporo4naja [7]

Answer:

10:00 am EST in Ohio

Step-by-step explanation:

Using the 50 States Time zones attached in the image below.

Chance who lives in Texas has a Time zone of CST (central standard time), while his cousin who lives in Ohio has a Time zone of EST(eastern standard time).

So if it is 5 pm in CST, it will be 6 pm in EST.

Given that;

Chance wants to wish his cousin in Ohio at 9:00 am CST, then the time it will be at his cousin's house when Chance calls to say happy birthday will be:

9:00 am + 1 = 10 :00 am EST in Ohio

6 0
3 years ago
4, 5, 6 is it a right triangle, acute, or obtuse
maxonik [38]

Answer:

it is an acute scalene triangle

3 0
4 years ago
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Put the following equation of a line into slope-intercept form, simplifying all fractions. x + 2y = 16​
mash [69]

Answer:

<h2>x + 2y = 16</h2>

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y=mx+b

Rewrite in slope-intercept form.

y= −1/2x+8

Step-by-step explanation:

Hope it is helpful...

8 0
3 years ago
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1.Give one number that makes the inequality x + 7 &gt; 20 true
nata0808 [166]
1. Any number above 13 works. Why? Because 20-7=13, and to be greater than 20, you must add a number larger than 13.

Examples: 14+7 > 20, 30+7 > 20, 100+7 > 20

2. Any number below 25/3 (which is also 8.3 with a repeating 3) works. Why? Because 25/3=8.3 with a repeating 3, and to remain less than 25, you must multiply by a number less than 8.3 with a repeating 3.

Examples: 3(8) < 25, 3(5) < 25, 3(0) < 25

3. 4 buses. 1 bus will hold 60 students, 2 will hold 120, 3 will hold 180, and 4 will hold 240. The question is trying to trick you into putting now 3.3333333333... buses because that's what 200/60 is, but there is no such thing as a third of a bus. So you need at least 4 buses. (There will be an extra 40 spaces for passengers on the 4th bus, but that is okay.)

To find this answer I did 200/60 and got 3.3 with a repeating 3. You must round to the higher whole number. Rounding down to 3 buses leaves you with 20 students without a bus.

4. 19 boxes. 18 boxes will only hold 288 candies. The question is trying to trick you into putting down 18.75 boxes because that's what 300/16 is, but there is no such thing as 75% of a box. So you need at least 19 boxes. (There will be an extra 4 spaces for candies in the 19th box, but that is okay.)

To find this answer I did 300/16 and got 18.75. You must round to the higher whole <span>number. Rounding down to 18 boxes leaves you with 12 candies without a box.</span>
6 0
4 years ago
Can someone please answer this I don’t understand!
Dovator [93]

The coordinates of X are (5, 11).

Solution:

Given points of the line segment are P(2, 2) and T(7, 17)  

Let X be the point that partitions the directed line segment PT in the ratio 3 : 2

Using section formula, we can find the coordinate of the point that partitions the line segment.

Section formula:

$X(x, y)=\left(\frac{m x_{2}+n x_{1}}{m+n}, \frac{m y_{2}+n y_{1}}{m+n}\right)

Here, x_{1}=2, y_{1}=2, x_{2}=7, y_{2}=17 and m = 3, n =2

Substitute these in the section formula,

$X(x, y)=\left(\frac{3 \times 7+2 \times 2}{3+2}, \frac{3 \times 17+2 \times 2}{3+2}\right)

            $=\left(\frac{21+4}{5}, \frac{51+4}{5}\right)

           $=\left(\frac{25}{5}, \frac{55}{5}\right)

           =(5, 11)

X(x, y) = (5, 11)

The coordinates of X are (5, 11).

6 0
3 years ago
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