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3 years ago

4, 5, 6 is it a right triangle, acute, or obtuse

Mathematics

2 answers:

Sladkaya [172]3 years ago

8 0

Answer:

Since the lengths of the triangle are 4,5, and 6, which are almost equal, then the triangle cannot be obtuse. It's right triangle

maxonik [38]3 years ago

3 0

Answer:

it is an acute scalene triangle

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Step-by-step explanation:

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The number of private investigators is expected to increase from 52,000 in 2006 to 61,000 in 2016. If there are 648,982 police o

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Ratio of sandwiches white bread to brown bread is 10:3. 2/3 white are vegetarian, half brown are vegetarian. What fraction of th

julsineya [31]

<h3>Answer:</h3>

8/13

<h3>Step-by-step explanation:</h3>

Given in the question

Ratio of sandwiches white bread to brown bread is 10 : 3

white bread fraction = 10/13

brown bread fraction = 3/13

It is also provided that

2/3 white are vegetarian

1/2 brown are vegetarian

for white bread vegetables sandwich we will find 2/3 of 10

20/3/13

for brown bread vegetable sandwich we will find 1/2 of 3

3/2/13

adding both

20/3/13 + 3/2/13

8/13 (approximate)

3 0

3 years ago

What is the solution for the equation StartFraction 5 Over 3 b cubed minus 2 b squared minus 5 EndFraction = StartFraction 2 Ove

wolverine [178]

Answer:

The solutions are:

$b=0,\:b=4$

Step-by-step explanation:

Considering the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

Solving the expression

$\frac{5}{3b^3-2b^2-5}=\frac{2}{b^3-2}$

$\mathrm{Apply\:fraction\:cross\:multiply:\:if\:}\frac{a}{b}=\frac{c}{d}\mathrm{\:then\:}a\cdot \:d=b\cdot \:c$

$5\left(b^3-2\right)=\left(3b^3-2b^2-5\right)\cdot \:2$

$5b^3-10=6b^3-4b^2-10$

$\mathrm{Switch\:sides}$

$6b^3-4b^2-10=5b^3-10$

$6b^3-4b^2-10+10=5b^3-10+10$

$6b^3-4b^2=5b^3$

$\mathrm{Subtract\:}5b^3\mathrm{\:from\:both\:sides}$

$6b^3-4b^2-5b^3=5b^3-5b^3$

$b^3-4b^2=0$

$Using\:the\:Zero\:Factor\:Principle:$ $if\:\mathrm ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)$

So,

$b=0,b-4=0$

$b=0,b=4$

Therefore, the solutions are:

$b=0,\:b=4$

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3 years ago

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F(x)=-2x-1 and g(x)=x^2-1. Find (fog)(-5).

serg [7]

Answer: - 49

Step-by-step explanation:

f(x) = -2x - 1

g(x) = $x^{2}$ - 1

fg(x) = f ( $x^{2}$ - 1) , we just put in the value of g(x) , the next thing is to substitute $x^{2}$ - 1 for the value of x in f(x) , that is

fg(x) = -2( $x^{2}$ - 1) - 1

fg(x) = -2 $x^{2}$ + 2 - 1

fg(x) = -2 $x^{2}$ + 1

Therefore : fg(-5) means we will substitute -5 for x in fg(x) , that is

fg(-5) = -2 ( $(-5)^{2}$ + 1

fg(-5) = -2(25) + 1

fg(-5) = -50 + 1

fg(-5) = -49

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4 years ago