Answer: k = -8/9j + -1/9m + 1
Step 1: Flip the equation.<span><span><span><span>−8j </span>− 9k </span>+ 9 </span>= m
</span>Step 2: Add -9 to both sides.<span><span><span><span><span>−8j </span>− 9k </span>+ 9 </span>+ −9 </span>= <span>m + −9</span></span><span><span><span>−8j </span>− 9k </span>= <span>m − 9
</span></span>Step 3: Add 8j to both sides.<span><span><span><span>−8j </span>−9k </span>+ 8j </span>= <span>m −9 + 8j</span></span><span><span>−9k </span>= <span><span>8j + m </span>−9
</span></span><span>Step 4: Divide both sides by -9.
-9k/-9 = 8j + m - 9/-9
</span><span>k = -8/9j + -1/9m + 1</span>
Answer:
both are 75 degrees
Step-by-step explanation:
the angles add up to 180, as they are also vertical angles
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Answer:
No it is still 11 feet from the water at 2 seconds
2.1651 seconds is when it will hit the water
Step-by-step explanation:
h(t) = -16 t^2 +75
This is the formula for the distance
The -16t^2 is due to gravity and the 75 is the height above the bridge
We want to know the height a t =2
h(2) = -16 (2)^2 +75
h(2) =-64 +75
h(2) = 11
The rock will be 11 ft above the water
When will the rock hit the water
h = 0
0 = -16 t^2 +75
Subtract 75 from each side
-75 = -16t^2 +75-75
-75 = -16t^2
Divide by -16
-75/-16 = -16t^2 /-16
75/16 = t^2
Take the square root of each side. We only take the positive square root since time must be positive
sqrt(75/16) =t
5/4 sqrt(3) = t
2.1651 seconds = t
