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steposvetlana [31]
3 years ago
6

Consider the following code segment. for (int a = 0; a < 10; a++) { for (int b = 10; b > a; b--) { System.out.print("#");

} } How many "#" symbols are printed as a result of executing the code segment?
Computers and Technology
1 answer:
Ket [755]3 years ago
6 0

Answer:

55

Explanation:

Given the codes as below:

  1.        for (int a = 0; a < 10; a++)
  2.        {
  3.            for (int b = 10; b > a; b--)
  4.            {
  5.                System.out.print("#");
  6.            }
  7.        }

There are two layer loops in the code. The outer loop (Line 1) will run for 10 iterations by traversing through a = 0 to a=9. However, the inner loop  (Line 3) will run for 10 + 9 +  8 + 7 +...+ 1 = 55 iterations.

Since the print statement is within the inner loop (Line 5) and therefore the number of printed "#" symbols is dependent on the number of iterations of the inner loop. There will be 55 "#" symbols printed.

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{

       integer i = start;

loop from j = start to j < end

       {

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{

swap (array[i],array[j])

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           }

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{

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               decrease i by 1;

           }

       }

swap (array[i] , array[end])

       return partition index i;

}

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