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steposvetlana [31]
4 years ago
6

Consider the following code segment. for (int a = 0; a < 10; a++) { for (int b = 10; b > a; b--) { System.out.print("#");

} } How many "#" symbols are printed as a result of executing the code segment?
Computers and Technology
1 answer:
Ket [755]4 years ago
6 0

Answer:

55

Explanation:

Given the codes as below:

  1.        for (int a = 0; a < 10; a++)
  2.        {
  3.            for (int b = 10; b > a; b--)
  4.            {
  5.                System.out.print("#");
  6.            }
  7.        }

There are two layer loops in the code. The outer loop (Line 1) will run for 10 iterations by traversing through a = 0 to a=9. However, the inner loop  (Line 3) will run for 10 + 9 +  8 + 7 +...+ 1 = 55 iterations.

Since the print statement is within the inner loop (Line 5) and therefore the number of printed "#" symbols is dependent on the number of iterations of the inner loop. There will be 55 "#" symbols printed.

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MariettaO [177]

Answer:

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#include <stdio.h>

#include <iostream>

#include <fstream>

using namespace std;

int main()

{

   //object created of file stream

   ofstream out;

   //file opened for writing

   out.open("numbers.txt");

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   for(int n=0; n<10; n++)

   {

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}

Explanation:

1. An object of the ofstream is created. The ofstream refers to output file stream. This is used to create file for write and append operations.

ofstream out;

2. The file named, numbers.txt, is opened using the open() method with the object of ofstream.

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3. The message is displayed to the user that the file is opened.

4. Inside a for loop, which executes 10 times, a random number is generated. This random number is written to the file and a new line inserted.

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7. When the loop ends, the file is closed using close() method with the object of ofstream.

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14. In other languages such as java or csharp, the code is written inside classes.

15. In cpp, all the code is written inside main() method.

16.    The screenshot of the output messages displayed is attached.

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