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Olin [163]
3 years ago
6

Find the distance between the two points in simplest radical form. (3,8) and (5, -1)​

Mathematics
1 answer:
ruslelena [56]3 years ago
7 0

Answer: irk

Step-by-step explanation:

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Rob is making a scale model of the Solar System on the school field. He wants the distance from the Sun to Jupiter to be 8 metre
ANEK [815]

Answer:

1 : 9.75 * 10⁷

Step-by-step explanation:

To find n, we have to divide the real distance by the scale distance. This is 7.8 * 10⁸ / 8 = 0.975 * 10⁸ = 9.75 * 10⁷ which means that the ratio is 1 : 9.75 * 10⁷.

3 0
4 years ago
The cost of a jacket increased from $65.00 to $72.15. What is the percentage increase of the cost of the jacket?
Karo-lina-s [1.5K]

Answer:

11%

Step-by-step explanation:

$72.15 - $65.00=$7.15 /$65.00=.11 or 11%

6 0
4 years ago
A bag contains green marbles and blue marbles,
dexar [7]

There are 13 green marbles in the bag.

Step-by-step explanation:

Total marbles = 18

Let,

Green marbles = x

Blue marbles = y

According to given statement;

The number of green marbles is 2 less  than 3 times the number of blue marbles.

x = 3y-2    Eqn 1

x+y=18      Eqn 2

Putting value of x from Eqn 1 in Eqn 2;

(3y-2)+y=18\\3y-2+y=18\\4y=18+2\\4y=20

Dividing both sides by 4

\frac{4y}{4}=\frac{20}{4}\\y=5

Putting y=5 in Eqn 1

x=3(5)-2\\x=15-2\\x=13

There are 13 green marbles in the bag.

Keywords: linear equation, substitution method

Learn more about linear equations at:

  • brainly.com/question/8054589
  • brainly.com/question/7932185

#LearnwithBrainly

8 0
4 years ago
Hwy can you please help me posted picture of question
anygoal [31]
The term with degree 4 is 5 x^{4}.

The coefficient of the term is the constant number that is being multiplied with the variable of the term. In case of 5 x^{4}, the variable is x raised to the power 4 and the constant term that is being multiplied to the variable is 5. 
So the coefficient of of term of degree 4 is 5.

Thus correct answer is option D
3 0
4 years ago
A substance with a half life is decaying exponentially. If there are initially 12 grams of the substance and after 70 minutes th
77julia77 [94]

Answer: 233 min

Step-by-step explanation:

This problem can be solved by the following equation:

A=A_{o} e^{-kt}  (1)

Where:

A=7 g is the quantity left after time t

A_{o}=12 g is the initial quantity

t=70 min is the time elapsed

k is the constant of decay for the material

So, firstly we need to find the value of k from (1) in order to move to the next part of the problem:

\frac{A}{A_{o}}=e^{-kt}  (2)

Applying natural logarithm on both sides of the equation:

ln(\frac{A}{A_{o}})=ln(e^{-kt})  (3)

ln(\frac{A}{A_{o}})=-kt  (4)

k=-\frac{ln(\frac{A}{A_{o}})}{t}  (5)

k=-\frac{ln(\frac{7 g}{12 g})}{70 min}  (6)

k=0.00769995 min^{-1}  (7)  Now that we have the value of k we can solve the other part of this problem: Find the time t for A=2 g.

In this case we need to isolate t from (1):

t=-\frac{ln(\frac{A}{A_{o}})}{k}  (8)

t=-\frac{ln(\frac{2 g}{12 g})}{0.00769995 min^{-1}}  (9)

Finally:

t=232.697 min \approx 233 min

5 0
3 years ago
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