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MaRussiya [10]
3 years ago
14

Geoff has a bag that contains 4 red marbles and 6 blue marbles. He chooses two marbles at random and does not replace them. What

is the probability that the first marble is blue and the second marble is red? A. B. C. D.
Mathematics
2 answers:
Margaret [11]3 years ago
7 0

Answer:

The answer is 4/15 hopefully this helps!

Virty [35]3 years ago
6 0

Answer: \frac{4}{15}

<u>Step-by-step explanation:</u>

First pick (blue)     and        Second pick (red)

             \frac{6}{10}                  x                    \frac{4}{9}

= \frac{6(4)}{10(9)}

= \frac{2(2)}{5(3)}

= \frac{4}{15}

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Help if possible.
skelet666 [1.2K]
A ) Length = 5 - 2 x
Width = 3 - 2 x
The area of the bottom:
A = L  x  W = ( 5 - 2 x ) ( 3 - 2 x ) = 15 - 10 x - 6 x + 4 x² = 
= 4 x² - 16 x + 15
b ) 4 x² - 16 x + 15 = 10
4 x² - 16 x + 5 = 0
x = (16 - √(256 - 80))/ 8 = ( 16 - 13.266 ) / 2
x = 0.34 in
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3 years ago
Please help, I can figure out 20 shares multiply by $117.98 =2359.69
11Alexandr11 [23.1K]

Answer:

The awnser is D hope this helps :)

Step-by-step explanation:


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3 years ago
The present shown below is a cube.<br> Find the surface area of the present.
Kruka [31]
To answer this you need to multiply 20 by 20. this gives 400cm
or you can also square 20
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3 years ago
Read 2 more answers
A machine that fills beverage cans is supposed to put 12 ounces of beverage in each can. The standard deviation of the amount in
erica [24]

Answer:

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

Step-by-step explanation:

Assuming the following data:"12.14 12.05 12.27 11.89 12.06

12.14 12.05 12.38 11.92 12.14"

We can calculate the sample deviation with this formula:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

n=10 represent the sample size

\alpha=0.05 represent the confidence level  

s^2 =0.0217 represent the sample variance

\sigma^2_0 =0.12^2= 0.0144 represent the value to verify

Null and alternative hypothesis

We want to determine whether the standard deviation differs from 0.12 ounce, so the system of hypothesis would be:

Null Hypothesis: \sigma^2 = 0.0144

Alternative hypothesis: \sigma^2 \neq 0.0144

The statistic can be calculated like this;

\chi^2 =\frac{n-1}{\sigma^2_0} s^2

\chi^2 =\frac{10-1}{0.0144} 0.0217 =13.54

The degrees of freedom are:

df=n-1=10-1=9

Now we can calculate the p value using the alternative hypothesis:

p_v =2*P(\chi^2 >13.54)=0.279

Since the p value is higher than the signficance level assumed of 0.05 we have enough evidence to FAIL to reject the null hypothesis and there is no evidence to conclude that the true deviation differs from 0.12 ounces

7 0
3 years ago
Simplify the expression square root 18 + square root 50 .
REY [17]
The answer is 11.3137085
8 0
3 years ago
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