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3 years ago

Which group of numbers is listed from least to greatest?

Mathematics

2 answers:

suter [353]3 years ago

6 0

it's c negative numbers are smaller

kaheart [24]3 years ago

6 0

Answer:

-4,|-2|, |3|, 5, |-7|

Step-by-step explanation:

-4,|-2|, |3|, 5, |-7| ==> -4,2,3,5,7

|-6|, -4, |-2|, -1, 0 ==> 6,-4,2,-1,0

-8, |-5|, -4, |3|, 6 ==> -8,5,-4,3,6

-6, |-3|, -3, 6, |-9| ==> -6,3,-3,6,-9

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Help! Will give brainliest.

jolli1 [7]

Answer:

A. You can see which shape the bases are, how many bases there are, how many faces there are, and how many edges there are.

B. The bases are ABC and DEF, and I know because they are two congruent triangles on two opposite sides of the shape.

6 0

3 years ago

Read 2 more answers

Find the absolute maximum and absolute minimum values of the function f(x, y) = x 2 + y 2 − x 2 y + 7 on the set d = {(x, y) : |

dsp73

Looks like $f(x,y)=x^2+y^2-x^2y+7$ .

$f_x=2x-2xy=0\implies2x(1-y)=0\implies x=0\text{ or }y=1$

$f_y=2y-x^2=0\implies2y=x^2$

If $x=0$ , then $y=0$ - critical point at (0, 0).
If $y=1$ , then $x=\pm\sqrt2$ - two critical points at $(-\sqrt2,1)$ and $(\sqrt2,1)$

The latter two critical points occur outside of $D$ since $|\pm\sqrt2|>1$ so we ignore those points.

The Hessian matrix for this function is

$H(x,y)=\begin{bmatrix}f_{xx}&f_{xy}\\f_{yx}&f_{yy}\end{bmatrix}=\begin{bmatrix}2-2y&-2x\\-2x&2\end{bmatrix}$

The value of its determinant at (0, 0) is $\det H(0,0)=4>0$ , which means a minimum occurs at the point, and we have $f(0,0)=7$ .

Now consider each boundary:

If $x=1$ , then

$f(1,y)=8-y+y^2=\left(y-\dfrac12\right)^2+\dfrac{31}4$

which has 3 extreme values over the interval $-1\le y\le1$ of 31/4 = 7.75 at the point (1, 1/2); 8 at (1, 1); and 10 at (1, -1).

If $x=-1$ , then

$f(-1,y)=8-y+y^2$

and we get the same extrema as in the previous case: 8 at (-1, 1), and 10 at (-1, -1).

If $y=1$ , then

$f(x,1)=8$

which doesn't tell us about anything we don't already know (namely that 8 is an extreme value).

If $y=-1$ , then

$f(x,-1)=2x^2+8$

which has 3 extreme values, but the previous cases already include them.

Hence $f(x,y)$ has absolute maxima of 10 at the points (1, -1) and (-1, -1) and an absolute minimum of 0 at (0, 0).

3 0

3 years ago

Okay, this is the last one. Ty for helping.

yawa3891 [41]

Answer:

128

Step-by-step explanation:

You get this by doing PEMDAS. We start with parenthises and then exponet so we do 4x4 which is 16 now we have 18-16+2 so we go in order and the anwser for the first line is 4 but we have an exponet so 16

now the second line we divide 1 and 4 we get 4 and now we multiply by 1/2 and we get 2. now we have 16/2 that is our anwser and we can put that to a whole number of 128

8 0

2 years ago

How will you know if the function is exponential given its equation?

Mashcka [7]

Answer: the "m" value (if using y=mx+b) will have" x" as an exponent

3 0

3 years ago

Read 2 more answers

The number 8,046 can be modeled using base ten blocks. How many of each type of block are needed to build the number?

MArishka [77]

Answer:

the first one