3. f(-6) = 12+1 =13
f(-2) = 4+1 = 5
f(0) =1
Range {1,5,13}
4. f(-2) = (-2)^3+1 =-7
f(-1) = (-1)^2 +1 =0
f(3) = (3)^3 +1 = 28
Range = {-7,0,28}
5.the sequence is arithmetic
d= -11+19 = 8
an = a1 + d(n-1)
an = -19 +8(n-1)
6.l =w+5
a =l*w
a(w) =(w+5) * w
a(w)= w^2 +5w
f(w) = w^2 +5w
f(8) = 8^2 +5(8)
f(8) = 64 +40
f(8) =104 in^2
Woah this looks really hard... I’m sorry if someone doesn’t answer try searching it up
-2x^2 + 11x - 4
To get this answer, you need to combine like terms. However, before this, remember that you are ADDING, so don’t accidentally subtract any numbers.
Then, just follow these steps:
2x^2 + (-4x^2) = -2x^2
5x + 6x = 11x
-7 + 3 = -4
And proceed to put them in the equation correctly.
Hope this helps!
The value of x is 8 when y = 12 if variables x and y have proportional relationship.
According to the given question.
Variables y and x have proportional relationship.
⇒ y ∝ x
Let k be the constant of proportionality.
⇒ y = kx
Also, it is given that
y = 21 when x = 14
Substitute the value of y = 21 and x = 14 in y = kx to find the value of k.
21 = k(14)
⇒ k = 21/14
⇒ k = 3/2
Therefore, the value of x when y = 12
y = kx
⇒ 12 = (3/2)x
⇒ 12 × 2 = 3x
⇒ 24 = 3x
⇒ x = 24/3
⇒ x = 8
Hence, the value of x is 8 when y = 12.
Find out more information about proportional relationship here:
brainly.com/question/12917806
#SPJ4
Assuming you meant is
The answer would be :
Hope this helps !
Photon
However, your equation seems weird :o
