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telo118 [61]
4 years ago
9

Which of the following is true about the function below (1/sqrt x+4)

Mathematics
2 answers:
-BARSIC- [3]4 years ago
7 0

the answer is

its domain is

(-4, infinity)

and this range is

(0, infinity)

i hope this can help !! :)

Dennis_Churaev [7]4 years ago
5 0
Its domain is[-10,∞) and its range is
(-∞,0) U (0,∞)
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Tresset [83]
Its 6f hope this helps :P



5 0
4 years ago
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Ben wants to try a new honey-glazed salmon recipe. He starts with 1 2/3 cups of honey. He uses 1/5 of it to make the glaze. How
GalinKa [24]

Answer:

1 1/3

Step-by-step explanation:

Firstly, 1 2/3 is converted into an improper fraction being 5/3. Next, 1/5 of 5/3 is one portion of 5 equal portions. You can split 5/3 into five equal portions of 1/3. Therefore, 1/3 cup of honey was used to make the honey glaze. Lastly, that is subtracted from the 1 2/3 to end up with 1 1/3.

8 0
3 years ago
The vertices of triangle FGH have coordinates F(−5, 2), G(−4, 2), and H(−4, 3). Which coordinates are the coordinates of the ver
Schach [20]
C
In order to calculate the new vertices, we simply add 1 to the value of x in each point since the translation is towards the positive x-axis and subtract 3 from the y values of each point since the translation is towards the negative y-axis.
5 0
3 years ago
Consider the hyperbola represented by the equation: (picture)
forsale [732]

Answer:

- The center of hyperbola is (-2 , 3)

- The left vertex, if the hyperbola opens horizontally, or the

  bottom vertex, if it opens vertically, is (-6 , 3)

- The other vertex is (2 , 3)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the x-axis is

  (x - h)²/a² - (y - k)²/b² = 1, Where

- The length of the transverse axis is 2a

- The coordinates of the vertices are (h ± a , k)

- The length of the conjugate axis is 2b

- The coordinates of the co-vertices are (h , k ± b)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

* Now lets solve the problem

∵ (x + 2)²/4² - (y - 3)²/5² = 1

∵  (x - h)²/a² - (y - k)²/b² = 1

∴ a = 4 , b = 5

∴ h = -2 , k = 3

∵ The center of the hyperbola is (h , k)

∴ The center of hyperbola is (-2 , 3)

∵ The coordinates of the vertices are (h + a , k)  , (h - a , k)

∴ The coordinates of the vertices are (-2 + 4 , 3)  , (-2 - 4 , 3)

∴ The coordinates of the vertices are (2 , 3)  , (-6 , 3)

∴ The left vertex, if the hyperbola opens horizontally, or the

  bottom vertex, if it opens vertically, is (-6 , 3)

∴ The other vertex is (2 , 3)

6 0
4 years ago
What is a correct congruence statement for the triangles shown?<br> Enter your answer in the box.
Nesterboy [21]

Answer:

ASA

Step-by-step explanation:

there are two congruent angles with an included side in between

6 0
1 year ago
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