The input to an exponential function is the initial value of the variable.
Plz look at the picture below.
Answer:
a. The given equation is d = -75·t + 275 is a function
b. f(t) = -75·t + 275
c. 275 km
d. The situation does not makes sense for t > 11/2 hours.
Step-by-step explanation:
a. Given that a relation is a functional relation if for each input of a member in the relation, there is only one output for the other member, therefore;
The given equation is d = -75·t + 275 is a function
As when t = 1, d = 200 km
b. The equation written in functional notation, f(t) is f(t) = -75·t + 275
c. At the start of the journey, t = 0
Therefore;
f(0) = -75×0 + 275 = 275 km
d. The values of t that do no make sense in the function are given as follows
0 = -75×t + 275
t = 275/75 = 11/3 = 3.67 hours
For times above 3.67, the distance becomes negative
Therefore, the situation does not makes sense for t > 11/2 hours.
1-) isolate the radical symbol on one side of the equation
2-) square both sides of the equation to eliminate the radical symbol
Remember:
a) (x,y) => (x, -y) is a reflection across X axis
b) (x,y) => (-x,y) is a reflection across Y axis
Here △RST is mapped to △R′S′T′ using the rule (x,y)→(x,−y)
Hence it is a reflection across X axis.
The size of the triangle does not alter.
But when this is followed by (x,y)→(3x,3y), the lengths increase by a factor 3.
Hence the triangles do not remain congruent.
△RST is not congruent to △R′S′T′ because the rules do not represent a sequence of rigid motions.
Option A) is the right answer
