Question

Which ordered pair can be included in the table of values shown below for the equation p=25x-2?

Answer 1

Answer:

(0,-2)

Step-by-step explanation:

So since you are given the equation, p=25x-2, all you really need to do is plug in the ordered pairs and see which satisfies the equation.

This means makes both side have the same number value.

Let's try (x,p)=(-2,-2):

 p=25x-2 with (x,p)=(-2,-2)

-2=25(-2)-2

-2=-50-2

-2=-52

-2 and -52 do not represent the same number so (-2,-2) is not a point on the given line.

Let's try (x,p)=(-2,0):

p=25 x -2 with (x,p)=(-2,0)

0=25(-2)-2

0=-50-2

0=-52

0 and -52 do not represent the same number so (-2,0) is not a point on the given line.

Let's try (x,p)=(0,-2):

p=25 x  -2 with (x,p)=(0,-2)

-2=25(0)-2

-2=0   -2

-2=-2

-2 and -2 are the same number and so (0,-2) is a point on the line.

Let's try (x,p)=(0,0)

p=25 x  -2 with (x,p)=(0,0)

0 =25(0)-2

0 =  0   -2

0 =   -2

0 and -2 are not the same number so (0,0) is not a point on this line.

Answer 2

Answer:

Option C) (0,-2) can be included in the table for the given equation.

Step-by-step explanation:

We are given the following information in the question:

x:          3           9           5           10

p:          73         223       123        248

$p = 25x-2$

A) (-2,-2)

Putting x = -2 in the above equation.

$p = (25\times -2)-2 = -52$

Hence, the given point does not lie in the table.

B) (-2,0)

Putting x = -2 in the above equation.

$p = (25\times -2)-2 = -52$

Hence, the given point does not lie in the table.

C) (0,-2)

Putting x = 0 in the above equation.

$p = (25\times 0)-2 = -2$

Hence, the given point lies in the table.

D) (0,0)

Putting x = 0 in the above equation.

$p = (25\times 0)-2 = -2$

Hence, the given point does not lie in the table.

Option C) (0,-2) can be included in the table for the given equation.