You're asking for three consecutive odd numbers, then
Let, the numbers = x, x+2, x+4
It is given that, x + x+2+ x+4 = -27
3x + 6 = -27
3x = -27 - 6
x = -33/3
x = -11
Then, x+2 = -9 & x+4 = -7
In short, Your Numbers would be: -7, -9,-11
Hope this helps!
Answer:
(-5,10)
Step-by-step explanation:
1. "the graph has the same zeros" : so let a be the "triple" root of the cubic polynomial function.
2. So f(x)=

3. Don't forget that the expression might have a coefficient b as well, and still maintain the conditions:

4. Now, f(0)=-5 so




5. the function is

where a can be any real number except 0