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Natali5045456 [20]
3 years ago
10

Determine if f(x)= x + 12/ x is even, odd, or neither

Mathematics
1 answer:
Reptile [31]3 years ago
3 0
F(-x)=-x+(12/-x)=-x-12/x
odd function
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Find the equation of the line that passes through the points (-800, 200) and<br> (-400, 300)
alisha [4.7K]

The distance (d) between two points (x1,y1) and (x2,y2) is given by the formula

d = √  ((X2-X1)2+(Y2-Y1)2)

d = √ (-400--800)2+(300-200)2

d = √ ((400)2+(100)2)

d = √ (160000+10000)

d = √ 170000

The distance between the points is 412.310562561766

The midpoint of two points is given by the formula

Midpoint= ((X1+X2)/2,(Y1+Y2)/2)

Find the x value of the midpoint

Xm=(X1+X2)/2

Xm=(-800+-400)/2=-600

Find the Y value of the midpoint

Ym=(Y1+Y2)/2

Ym=(200+300)/2=250

The midpoint is: (-600,250)

Graphing the two points, midpoint and distance

P1 (-800,200)

P2 (-400,300)

Midpoint (-600,250)

The length of the black line is the distance between the points (412.310562561766)

6 0
3 years ago
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What did the scout say after fixing the little old lady's bicycle horn?
Mnenie [13.5K]
After scout fixed the little old lady's bicycle horn, scout said Beep Repaired.
8 0
3 years ago
What is 1,002,003 rounded to the ten thousand place
Y_Kistochka [10]

1,002,003 rounded to the ten thousand place is 1,000,000

5 0
3 years ago
"Lito had some marbles. He gave ½ of his marbles plus 1 to Felix, ½ of the remaining marbles plus 1 to Ces, and ½ of the last re
Nuetrik [128]

let

x-------> total amount of marbles at the beginning


we know that

1) He gave ½ of his marbles plus 1 to Felix

(1/2)*x+1=(x+2)/2 (Felix's marbles)

remaining=x-[(x+2)/2]-----> [2x-x-2]/2------> (x-2)/2


2)½ of the remaining marbles plus 1 to Ces

(1/2)*[(x-2)/2]+1=[(x-2)/4]+1-----> (x+2)/4 (Ce's marbles)

remaining=[(x-2)/2]-[(x+2)/4]-----> [2x-4-x-2]/4------> (x-6)/4


3) ½ of the last remaining marbles plus 1 to Pedro

(1/2)*[ (x-6)/4]+1=[(x-6)/8)+1------> (x+2)/8 (Pedro's marbles)

remaining=[(x-6)/4]-[(x+2)/8]------> [2x-12-x-2]/8-----> (x-14)/8


4)If Lito had 1 marble left for himself

so

the last remaining is equal to 1

(x-14)/8=1-----> x-14=8------> x=22 marbles


Verify

(x+2)/2 (Felix's marbles)------> (22+2)/2=12

(x+2)/4 (Ce's marbles)------> (22+2)/4=6

(x+2)/8 (Pedro's marbles)---> (22+2)/8=3

Lito's marbles------------------> 1

total=12+6+3+1=22--------> is ok


therefore


the answer is

the total amount of marbles at the beginning was 22

4 0
3 years ago
Is this answer correct?
hodyreva [135]

Answer:

No

Step-by-step explanation:

How to solve :

(a-4)/(a^2+8a+12)*(a^2-2a-48)/(a^2+4a-32)

Factor:

a^2+8a+12 = (a+6)(a+2)

a^2-2a-48 = (a-8)(a+6)

a^2+4a-32 = (a+8)(a-4)

simplify a+6, and a-4

you are left with (a-8)/(a+2)(a+8) = (a-8)/(a^2+10x+16)

8 0
3 years ago
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