The reaction force exerted by the floor of the elevator on the man is D.944 N
Step-by-step explanation:
When the elevator is accelerating upwards at 2 m/s² there occurs a fictitious force acting downwards to produce a downward acceleration of 2 m/s².
The formula to apply here is ;
Weight due to gravity=mg where m is mass of the man and g is acceleration due to gravity.
Due to additional downward acceleration the total acceleration downwards will be : 9.8+2 = 11.8 m/s²
The man weighs down on the elevator floor with a force of ;
F=m(a+g) where m is mass of man, a is acceleration
F=80( 9.8+2)
F=80(11.8)= 944 N
The reaction force by the floor of the elevator is thus 944 N
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Elevator physics :brainly.com/question/13464055
Keywords : elevator, acceleration, moving upwards, reaction force, floor
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This is the correct answer
Answer:
Step-by-step explanation:
Let's say the number is 9. 10% of 9 is 0.9. Add that to 9 and you would get 9.9. 10% of 9.9 is 0.99. Subtract and you would get 8.91. Then you could do the rest.
