Show that every member of the family of functions y = (6 ln(x) + C)/x , x > 0, is a solution of the differential equation x2y
' + xy = 6. (Simplify as much as possible.) y = 6 ln(x) + C x ⇒ y' = 6x · (1/x) − (6 ln(x) +C) x2 LHS = x2y' + xy = x2 · x2 + x · 6 ln(x) + C x = + 6 ln(x) + C = = RHS, so y is a solution of the differential equation.
1 answer:
You might be interested in
Answer:
6/5 or 1 1/5
Edit:
soo
=
since they both are being multipled to the square root of 5, you can just add them (i think)
Step-by-step explanation:
6 times the square root of 5
you add 4 and 2