Cross multiply and divide
Put 191 over 238 (like a fraction) the put another fraction bar right next to your first fraction and put 100 on bottom (this equals a whole in % and it's right across from the total of 238 free throws) then multiply 191 by 100 then divide by 238 and that answer should be your the percent you need.
The answer is: [A]: " -53 " .
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Explanation:
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Given:
" Let f(x) = -2x −<span> 7 and g(x) = -4x + 3. Find (f o g)(-5) " ;
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First, find g(-5) . g(x) = -4x + 3.
g(-5) = -4*(-5) + 3 = 20 + 3 = 23 ;
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Now find f (g(-5) to get the answer; that is f(23);
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Find f(23). f(x) = -2x </span>− 7 .
f(23) = (-2*23) − 7 = -46 <span>− </span>7 = -53 ; which is "Answer choice: [A]" .
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Answer:
Hi! The correct answer is 16!
Step-by-step explanation:
<em><u>~Use the formula (b/2)^2 in order to create a new term to complete the square~</u></em>
<h3>
Answer: 14x - 8</h3>
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Explanation:
I'll use the quadratic formula to find the roots or x intercepts. This slight detour allows us to factor without having to use guess-and-check methods.
The equation is of the form ax^2+bx+c = 0
This leads to...

Now use those roots to form these steps

Refer to the zero product property for more info.
Therefore, the original expression factors fully to (4x-5)(3x+1)
Use the FOIL rule to expand it out and you should get 12x^2-11x-5 again.
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We did that factoring so we could find the side lengths of the rectangle.
I'm using the fact that area = length*width
- L = length = 4x-5
- W = width = 3x+1
The order of length and width doesn't matter.
From here, we can then compute the perimeter of the rectangle
P = 2(L+W)
P = 2(4x-5+3x+1)
P = 2(7x-4)
P = 14x - 8
Answer:
1 hour = 7/18 of the distance between two ports
Step-by-step explanation:
Given that:
In 3/7 hours distance traveled is 1/6
For finding distance in one hour, divide both sides by 7/3 so that 3/7 would be cancelled out:
3/7 * 7/3 hours = 1/6 * 7/3 distance
By simplifying:
1 hour = 7/18 of the distance between two ports
This means that in one hour 7/18 of the distance is covered between two ports.
i hope it will help you!