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postnew [5]
3 years ago
8

The maximum weight your office building's elevator can carry is 1,500 pounds. You

Mathematics
1 answer:
Serggg [28]3 years ago
7 0

Answer:

50n+140=1500

Step-by-step explanation:

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X=1

Step-by-step explanation:

Snorkel, mask, and flippers Slope: 2 (so in the equation, it would look like 2x).

Snorkel, mask, and flippers Y-intercept: 10 (12 - 2 = 10, which is 0 hours, possibly the initial amount)

Snorkel, mask, and flippers Slope intercept form: y = 2x + 10

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3 years ago
The middle 83.12% of all Z values are between
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What is area?? <br> Here is the question I’m trying to answer <br><br> Part B
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4 years ago
The sides of a octagon each have a length of 8x inches.write an expression for the Perimeter of the octagon in inches
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8(8x)

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6 0
3 years ago
Radioactive Decay:
Vadim26 [7]

The question is incomplete, here is the complete question:

The half-life of a certain radioactive substance is 46 days. There are 12.6 g present initially.

When will there be less than 1 g remaining?

<u>Answer:</u> The time required for a radioactive substance to remain less than 1 gram is 168.27 days.

<u>Step-by-step explanation:</u>

All radioactive decay processes follow first order reaction.

To calculate the rate constant by given half life of the reaction, we use the equation:

k=\frac{0.693}{t_{1/2}}

where,

t_{1/2} = half life period of the reaction = 46 days

k = rate constant = ?

Putting values in above equation, we get:

k=\frac{0.693}{46days}\\\\k=0.01506days^{-1}

The formula used to calculate the time period for a first order reaction follows:

t=\frac{2.303}{k}\log \frac{a}{(a-x)}

where,

k = rate constant = 0.01506days^{-1}

t = time period = ? days

a = initial concentration of the reactant = 12.6 g

a - x = concentration of reactant left after time 't' = 1 g

Putting values in above equation, we get:

t=\frac{2.303}{0.01506days^{-1}}\log \frac{12.6g}{1g}\\\\t=168.27days

Hence, the time required for a radioactive substance to remain less than 1 gram is 168.27 days.

7 0
3 years ago
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