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Shtirlitz [24]
3 years ago
14

Find the illegal values of c in the multiplication statement c^2-3c-10/c^2+5c-14 times c^2-c-2/c^2-2c-15

Mathematics
1 answer:
Citrus2011 [14]3 years ago
3 0

Answer: c ≠ {-7, -3, 2, 5}

<u>Step-by-step explanation:</u>

  \frac{c^{2} - 3c - 10}{c^{2} + 5c - 14} * \frac{c^{2} - c - 2}{c^{2} - 2c - 15}

= \frac{(c - 5)(c + 2)}{(c + 7)(c - 2)} * \frac{(c - 2)(c + 1)}{(c - 5)(c +3)}

restrictions:

c + 7 ≠ 0           c - 2 ≠ 0          c - 5 ≠ 0          c + 3 ≠ 0

    c ≠ -7                 c ≠ 2               c ≠ 5                c ≠ -3

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13. Jody is supplying his food truck for the week. He buys 32 pounds of pork and 50 pounds of chicken for a total of $185. He re
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Answer:

Pork is $1.75 per pound (x=1.75)

Chicken is $2.58 per pound (y=2.58)

Step-by-step explanation:

<u>Key skills needed for this problem: Linear Equations, Systems, Elimination</u>

1) Use x and y for the pork and the chicken and you will get 2 equations:

  • 32x + 50y = 185
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We can use elimination in this system.

2) To use elimination, we can multiply the 2nd equation by -4:

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3) Next add both equations:

32x + 50y = 185

+

-32x - 80y = -262.4

-----------------------------

-30y = -77.4

y = $2.58

4) Next we can substitute the y value into one of the equations. I like the first one so I used that one ---> 32x + 50(2.58) = 185

50(2.58) is equal to 129 so ---> 32x + 129 = 185

                                                           -129     -129

                                                   ------------------------

                                                    32x = 56

                                       Divide by 32 and get x= $1.75

5) Therefore, It is $1.75 per pound of pork, and $2.58 per pound of beef.

<em>Hope you understood and have a nice day!! :D</em>

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