Find the two Z-scores that separate the middle 73.72% on the Standard Normal Curve.

Mathematics

1 answer:

leonid [27]3 years ago

4 0

Answer:

+1.12 and -1.12

Step-by-step explanation:

Let the two z scores be $-z_1and+z_1$ .

Since the two Z-scores that separate the middle 73.72% on the Standard Normal Curve, this can be represented by the equation:

$P(-z_1$

From the z table of the normal distribution, z₁ = 1.12. That is a z score of 1.12 gives 0.8686.

The two z scores are +1.12 and -1.12 = ± 1.12

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