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2 years ago

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The numerator of a rational number is greater than its denominator by 3. If the new number becomes 13/4 when the numerator is tr

ipled and the denominator is decreased by23, find the original number.

1 answer:

GarryVolchara [31]2 years ago

6 0

Answer:

Step-by-step explanation:

Let x represent the numerator and y represent the denominator.

The numerator of a rational number is greater than its denominator by 3. It means that

x = y + 3

If the new number becomes 13/4 when the numerator is tripled and the denominator is decreased by 23, it means that

3x/(y - 23) = 13/4

Cross multiplying, it becomes

3x × 4 = 13(y - 23)

12x = 13y - 299- - - - - - - - - - -1

Substituting x = y + 3 into equation 1, it becomes

12(y + 3) = 13y - 299

12y + 36 = 13y - 299

13y - 12y = 36 + 299

y = 335

x = y + 3 = 335 + 3

x = 338

The original number is 338/335

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3 years ago

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<h2>The missing measures of the angles are:</h2>

$m\angle 1= 60^{\circ}\\\\m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

<u>Given</u>:

$m\angle Z = 138^{\circ}$

<em><u>Note the following:</u></em>

An equilateral triangle has all its three angles equal to each other. Each angle = $60^{\circ}$ .

This implies that, since $\triangle WXY$ is equilateral, therefore, $m\angle Y = m\angle XWY = m\angle XYW = 60^{\circ}$

Base angles of an isosceles triangle are congruent to each other.

This implies that, since $\triangle WZY$ is isosceles, therefore, $m\angle 3 = \angle 5$

Applying the above stated, let's find the measure of each angle:

Find $m\angle 1$

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Find $m\angle 2$

$m\angle 2 = 60 - m \angle 3$

$m\angle 2 = 60 -\frac{1}{2}(180 - 138)$ $(Note: \frac{1}{2}(180 - 138) = 1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 2 = 60 -21\\\\m\angle 2 = 39^{\circ}$

Find $m\angle 3$ and $m\angle 5$ (base angles of isosceles triangle WZY)

$m\angle 3 = \frac{1}{2}(180 - 138) (1 $ base $ angle $ of $ \triangle WZY)$

$m\angle 3 = \frac{1}{2}(42) \\\\m\angle3 = 21^{\circ}$

$m\angle3 = m\angle 5$ (base angles of isosceles triangle are congruent)

Therefore,

$m\angle5 = 21^{\circ}$

Find $m\angle 4$

$m\angle 4 = 60 - m\angle 5$

Substitute

$m\angle 4 = 60 - 21\\\\m\angle 4 = 39^{\circ}$

The missing measures of the angles are:

$m\angle 1= 60^{\circ}\\\\ m\angle 2= 39^{\circ}\\\\m\angle 3= 21^{\circ}\\\\m\angle 4 = 39^{\circ}\\\\m\angle 5 = 21^{\circ}$

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Hey there :)

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