If n is an integer, then cos(n(2<span>π))=1.
Take n=0, cos(2</span>π)=cos(0)=1, n=1, cos(2π)=1, n=2, cos(2(2π))=cos(4<span>π)=cos(0)=1...
If n is not an integer, well, ..... we don't know the value, which depends on the value of n.</span>
Answer:
Step-by-step explanation:
Step-by-step explanation:
Since we are told that 10 is a zero,
(x−10) must be a factor:
F(x)=2x3−14x2−56x−40
F(x)=(x−10) (2x2+6x+4)
F(x)=2(x−10)(x2+3x+2)
F(x)=2(x−10)(x+2)(x+1)
So the other two zeros are
x = -2 and x= −1
Answer:
In interval form range is [-2,16]
Step-by-step explanation:
Here we can see that given equation is circle
whose center is (5,7 ) and radius is 8 ,
Range of the circle is actually values of y it changes from
if (h,k) is the center and r is the radius of circle then range is given by
k-r ≤y ≤ k+r
here in the question k = 7 and r =9
therefore range is
7-9 ≤y ≤ 7+9
-2 ≤y ≤ 16
In interval form [-2,16]
I’m pretty sure it’s A and C
