What is x x+5+X+9=90

Greg needs to buy plastic spoons. Brand A has a box of 25 spoons for $1.99 . Brand B has a box of 42 spoons for $3.89 . Find the

Helga [31]

To find the price per spoon of brand A, divide the cost by the amount of spoons:

1.99 / 25 = 0.0796

Repeat this process for brand B:

3.89 / 42 = 0.0926

Brand A, at $0.08 a unit, is the better buy of brands A and B.

Hope this helps.

8 0

3 years ago

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How do I solve w, squared, minus 81.

andreyandreev [35.5K]

Nhnhb uujjjjjjnj b fuvuvuvvyvuvu bib bib in bibibibk. bibibibibibk ivuvivycuvuvuv jbibivibivuc ivvivibi

4 0

2 years ago

Let N be the universal set and A, B, C, D be its subsets given by A={x:xisaevennaturalnumber},B={x:xNandxisamultipleof3} C={x:x

Svet_ta [14]

Answer:

$A^{'}$ = {1,3,5,7,9,....}

$B^{'}$ = {1,2,4,5,7,8,10,11,13,14......}

$C^{'}$ = {1,2,3,4,5}

$D^{'}$ = {10,11,12,13,14,15,......}

Step-by-step explanation:

Solution:

It is given that, Universal set is the set of all Natural Numbers.

and

Set A, Set B, Set C, Set D are subsets of Universal set.

A = {x:x is even natural numbers} = {2,4,6,8,10,.....}

B = {x:x ∈ N and x is a multiple of 3} = {3,6,9,12,15,....}

C = {x:x∈ N and x < 5} = {6,7,8,9,10,.....}

D = {x:x ∈ N and x > 10} = {1,2,3,4,5,6,7,8,9}

U = {1,2,3,4,5,6,7,8,9,10,11,........}

Complements:

$A^{'}$ = U-A = {1,2,3,4,5,6,7,8,9,10,11,........} - {2,4,6,8,10,.....}

$A^{'}$ = {1,3,5,7,9,....}

$B^{'}$ = U-B = {1,2,3,4,5,6,7,8,9,10,11,........} - {3,6,9,12,15,....}

$B^{'}$ = {1,2,4,5,7,8,10,11,13,14......}

$C^{'}$ = U-C = {1,2,3,4,5,6,7,8,9,10,11,........} - {6,7,8,9,10,.....}

$C^{'}$ = {1,2,3,4,5}

$D^{'}$ = {1,2,3,4,5,6,7,8,9,10,11,........} - {1,2,3,4,5,6,7,8,9}

$D^{'}$ = {10,11,12,13,14,15,......}

8 0

2 years ago

Prove tan(θ / 2) = sin θ / (1 + cos θ) for θ in quadrant 1 .

Leona [35]

We are asked to prove tan(θ / 2) = sin θ / (1 + cos θ). In this case, tan θ is equal to sin θ / cos θ. we can apply this to the equality. sin θ is equal to square root of (1-cos θ)/2 while cos θ is equal to square root of (1 + cos θ)/2.
Hence, when we replace cos θ with square root of (1-cos θ)/2, we can prove already.

3 0

3 years ago

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Is the binomial a factor of the polynomial function?

olchik [2.2K]

Answer:

YES

NO

Step-by-step explanation:

The given polynomial is: $f(x) = x^3 + 4x^2 - 25x - 100$

(x - a) is a factor of a polynomial iff x = a is a solution to the polynomial.

To check if (x - 5) is a factor of the polynomial f(x), we substitute x = 5 and check if it satisfies the equation.

∴ f(5) = 5³ + 4(5)² - 25(5) - 100

= 125 + 100 - 125 - 100

= 225 - 225

= 0

We see, x = 5 satisfies f(x). So, (x - 5) is a factor to the polynomial.

Now, to check (x + 2) is a factor.

i.e., to check x = - 2 satisfies f(x) or not.

f(-2) = (-2)³ + 4(-2)² - 25(-2) - 100

= -8 + 16 + 50 - 100

= -108 + 66

≠ 0

Therefore, (x + 2) is not a factor of f(x).

To check (x - 4) is a factor.

∴ f(4) = 4³ + 4(4)² - 25(4) - 100

= 64 + 64 - 100 - 100

= 128 - 200

≠ 0

Therefore, (x - 4) is not a factor of f(x).

7 0

2 years ago