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Tju [1.3M]
4 years ago
15

3 On a coordinate grid, the location of a lighthouse is at L, and the location of a buoy is at B. At noon, a ship is at the midp

oint of the segment connecting the buoy and the lighthouse on the grid. Find the coordinates that best represent the ship's position at noon?​

Mathematics
1 answer:
Zarrin [17]4 years ago
5 0

Answer:

(\frac{1}{2}, 2)

Step-by-step explanation:

Using the midpoint formula, M(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}), we can find the coordinates that represents the position of the ship at noon.

Let L(-4, 7) = (x_1, y_1) (given on the coordinate plane)

B(5, -3) = (x_2, y_2) (given also)

Plug in the values into the formula and solve as follows:

M(\frac{-4 + 5}{2}, \frac{7 +(-3)}{2})

M(\frac{1}{2}, \frac{7 - 3}{2})

M(\frac{1}{2}, \frac{4}{2})

M(\frac{1}{2}, 2)

Position of the ship at noon is best represented at (\frac{1}{2}, 2)

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A car travels along a straight stretch of road. It proceeds for 16.2 mi at 57 mi/h, then 24.6 mi at 44 mi/h, and finally 45.1 mi
LekaFEV [45]

Answer:

The average velocity the entire trip was 43.25 mi/h

Step-by-step explanation:

In this case we have to calculate an average based on the miles traveled. First we have to calculate the total of miles traveled, then calculate the portion of the total travel of each and with this calculate the average speed during the trip. First the total miles traveled:

TotalMiles=16.2+24.6+45.1=85.9

Now the percentages:

At 57 mi/h were \frac{16.2}{85.9}=0.19

At 44 mi/h were \frac{24.6}{85.9}=0.29

At 37.8 mi/h were \frac{45.1}{85.9}=0.52

Now multiplying the speed by the portion and summing them we can have the average velocity:

57*0.19+44*0.29+37.8*0.52=43.25

The average velocity the entire trip was 43.25 mi/h

5 0
3 years ago
Help please! Please put the answers numbered!
Nesterboy [21]
1: ‘8’/3x = 1+ 5/3x
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3: ‘3’/3x=1
4: 1
4 0
3 years ago
Write the numer 3 1/2 in a/b form
hichkok12 [17]

Answer: 7/2

Step-by-step explanation:

3  1/2 in a/b form = 7/2

Hope it helped u,

pls mark as the brainliest

^_^

4 0
3 years ago
Find a degree 3 polynomial with real coefficients having zeros 4 and 2i and a lead coefficient of 1. Write P
iren2701 [21]

Answer:

x^2 - 2xi - 4x +8i

Step-by-step explanation:

(x -4) (x -2i) (x+2i)

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The owners of a large pet store have determined that 65\ee, percent of their customers own dogs. They select 151515 customers at
crimeas [40]

Answer:

D is a binomial random variable with p = 0.65, n = 15

Step-by-step explanation:

For each customer, there are only two possible outcomes. Either they have dogs, or they do not. The probability of a customer having a dog is independent of any other customer. This means that D is a binomial random variable.

Binomial probability distribution

Probability of exactly x successes on n repeated trials, with p probability.

65% of the customers have dogs:

This means that p = 0.65

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This means that n = 15

What type of variable is D?

D is a binomial random variable with p = 0.65, n = 15

5 0
3 years ago
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