<span>5(x – 2)(x + 4) > 0
(5x-10)(x+4)>0
6x -6 > 0
+6 +6
6x >
</span>x<-4 or x>2
Answer:

Given:
- area = 18 cm²
- base = 6 cm
- height = (h + 1) cm
Substitute the given values into the equation and solve for h:



expand using distributive property of addition
:

subtract 3 from both sides:

divide both sides by 3:

<u>To verify</u>:
Half of the base is 3 cm.
If h=5, then the height of the triangle is 6 cm.
Multiplying 3 by 6 is 18.
This matches the given area, so we can verify that h = 5.
Given:
The function, f(x) = -2x^2 + x + 5
Quadratic equation: 0 = -2x^2 + x +5
where a = -2
b = 1
c = 5
The discriminate b^2 - 4ac = 41
To solve for the zeros of the quadratic function, use this formula:
x = ( -b +-√ (b^2 - 4ac) ) / 2a
x = ( 1 + √41 ) / 4 or 1.85
x = ( 1 - √41 ) / 4 or -1.35
Therefore, the zeros of the quadratic equation are 1.85 and -1.35.
I believe the answer is 1 because the line is negative and has a slope of 1/2 so -1/2 and it crosses at 8