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Lena [83]
2 years ago
12

Kenya plans to make a down payment plus monthly payments in order to buy a motorcycle. At one dealer she would pay $2,350 down a

nd $200 each month. At another dealer, she would pay $2,750 down and $175 each month. After how many months would the total amount paid be the same for both dealers? What would that amount be?
After
_____months Kenya will have paid $_____
for the bike at either dealer.
Mathematics
1 answer:
vovangra [49]2 years ago
8 0

Answer:

After 16 months, Kenya will have paid $5,550

Step-by-step explanation:

This is a guess and check type of a problem.  You guess a number of months, plug it into x, and see if both equations come out with the same answer.

 If you plug 16 into the first dealer's equation, you get y= 200(16) + 2350.  Solving this equation will mean y equals 5550.

If you plug 16 into the second dealer's equation, you get y= 175(16) + 2750.

Solving this equation will mean y also equals 5550.

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valentina_108 [34]

By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right)  is sum of cubes

<h3>What is formula of sum of cubes and difference of cubes?</h3>

Formula of sum of cubes and difference of cubes are following

(a+b)(a^2 -ab +b^2) = a^3+ b^3 \\\\\\(a - b)(a^2+ ab+ b^2) = a^3 - b^3

(a)

(x-4) \left(x^{2}+4 x-16\right)\\=(x-4) \left(x^{2}+4 x-4^2\right)\\\\

by comparison with formula we can say that this is neither sum or nor difference of cubes.

(b)

(x-1)\left(x^{2}-x+1\right)\\=(x-1)\left(x^{2}-x+1^2\right)

by comparison with formula we can say that this is neither sum nor difference of cubes.

(c)

(x+1)(x-1)=x^{2}-1^{2}\\

we can say that this is neither sum  nor difference of cube as it's difference of squares.

(d)

(x+4)\left(x^{2}-4 x+16\right)\\\\(x+4)\left(x^{2}-4 x+4^2\right)

by comparison with formula this is equal to

x^{3}+4^{3}\\

Hence this is sum of cubes

(e)

(x+4)\left(x^{2}+4 x+16\right)\\(x+4)\left(x^{2}+4 x+4^2\right)

by comparison with formula we can say that this is neither sum  nor difference of cubes.

By comparing all the options with the formula of sum of cubes and difference of cubes we get that  (x+4)\left(x^{2}-4 x+16\right) is sum of cubes

To know more about cubes visit: brainly.com/question/107100

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