Does any one know how to do this problem correctly? : (3-c^2d)(4-2c^2d)
1 answer:
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Answer:
Dimensions are length 15 feet and width 30 feet.
Maximum area of the plot is 450 feet².
Step-by-step explanation:
Let the length of the plot = x feet and width = y feet.
Since, the amount of fencing to be applied on the three sides of the plot is 60 feet.
We have,
i.e.
Now, Area of the rectangular plot = Length × Width
i.e. Area of the rectangular plot =
i.e. Area of the rectangular plot =
i.e. Area of the rectangular plot =
<em>Since, the maximum of the quadratic equation will be obtained at
.</em>
Then, the maximum of the area of the plot is at the point i.e. x= 15
Then, maximum area of the rectangular plot =
i.e. maximum area of the rectangular plot =
i.e. maximum area of the rectangular plot = -450+900 = 450 feet²
Hence, Maximum area of the plot is 450 feet².
Then, implies
i.e. y= 30.
Hence, the maximum area is enclosed by the length 15 feet and width 30 feet.