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Kay [80]
3 years ago
13

Hey what the answerall the formulas of exponents ​

Mathematics
2 answers:
Snowcat [4.5K]3 years ago
8 0

Answer:

<u>I</u><u> </u><u>hope</u><u> </u><u>the</u><u> </u><u>above</u><u> </u><u>picture</u><u> </u><u>help</u><u> </u><u>you</u><u> </u><u>mate</u><u> </u>

<u>have</u><u> </u><u>a</u><u> </u><u>great</u><u> </u><u>day</u><u> </u>

I did it in white board so that I can explain better.i hope you understand if u have any problem in understanding be sure to reach out

<u>#liliflim</u>

jolli1 [7]3 years ago
3 0

Answer:

see below

Step-by-step explanation:

all formulas of exponent given by:

\displaystyle {x}^{1}  = x  \stackrel{ \rm example}{ \iff} 2^{1}  = 2

\displaystyle{x}^{0}  = 1\stackrel{ \rm example}{ \iff} 2^{0}  = 1

\rm \displaystyle {x}^{m} \cdot  { x }^{n}   =  {x}^{m + n}  \stackrel{ \rm example}{ \iff} x^{1 } \cdot  {x}^{2}   = x^{1 + 2 } =  {x}^{3}

\displaystyle \sqrt[n]{{x} }= x^{1/n} \stackrel{ \rm example}{ \iff} \sqrt[3]{x}  = x^{1/3}

\rm \displaystyle  \frac{{x}^{m}  }{ { x }^{n}}   =  {x}^{m  - n}  \stackrel{ \rm example}{ \iff}  \frac{x^{3} }{ {x}^{1}  } = x^{3  -  1} =  {x}^{2}

\rm \displaystyle ({x}^{m} {)}^{n} =  {x}^{m n}  \stackrel{ \rm example}{ \iff} (x^{1 } {)}^{2}  = x^{ 2 }

\rm \displaystyle ({x}^{m} {y}^{m}  {)}^{n} =  {x}^{m n}  {y}^{mn}  \stackrel{ \rm example}{ \iff} (x^{1 } { {y}^{1} )}^{2}  = x^{ 2 }  {y}^{2}

\rm \displaystyle   \left(\frac{{x}^{}  }{ { y }^{}}  \right) ^{m}   =  \frac{{x}^{m}  }{ { y }^{n} } ^{}    \stackrel{ \rm example}{ \iff}   =   \left(\frac{ {x}^{2} }{ {y}^{2} }  \right)^{2}  = \frac{ {x}^{4} }{ {y}^{4} }

\displaystyle {x}^{ - n}  =  \frac{1}{ {x}^{n} }  \stackrel{ \rm example}{ \iff} x^{ - 2}  =  \frac{1}{ {x}^{2} }

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7 0
3 years ago
Find an exact value cos(19pi/12)
dmitriy555 [2]

cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}

Step-by-step explanation:

We know that

          cos 2x = 2cos²x - 1

So we have

          cosx=\sqrt{\frac{1+cos2x}{2}}

Substituting x=\frac{19\pi}{12}

         cos\left ( \frac{19\pi}{12}\right )=\sqrt{\frac{1+cos2\left ( \frac{19\pi}{12}\right )}{2}}\\\\cos\left ( \frac{19\pi}{12}\right )=\sqrt{\frac{1+cos\left ( \frac{19\pi}{6}\right )}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{1+cos570}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}}\\\\cos\left ( \frac{9\pi}{12}\right )=\sqrt{\frac{2-\sqrt{3}}{4}}\\\\cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}

   cos\left ( \frac{9\pi}{12}\right )=\frac{\sqrt{2-\sqrt{3}}}{2}

3 0
3 years ago
Read 2 more answers
. (a + b)2 – (2a – b)
inn [45]

Answer:

(-b) is the answer.

Step-by-step explanation:

2(a-b)-(2a-b)

=2a-2b-2a+b (opening the brackets)

= -b

Hope this helps you buddy. Have a nice day^_^.

If you have doubt then you can ask in comments. I will surely answer.

3 0
3 years ago
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Consider the following functions.<br> f(x) = x^2- 4<br> g(x) = x-2<br> What is (f(x)) (g(x))?
rodikova [14]

Answer:

(f(x) g(x)) = x^3-2x^2-4x+8 ; all real numbers

Step-by-step explanation:

(f(x) g(x)) = (x^{2} -4)(x-2)

              = x^3-2x^2-4x+8  via FOIL

6 0
3 years ago
The of choice are ways epress 0.4 which is not
Ann [662]

Answer:

NO IT IS 4

Step-by-step explanation:

6 0
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