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Bas_tet [7]
3 years ago
8

What are the common multiples of 8,10,12?

Mathematics
2 answers:
timurjin [86]3 years ago
4 0

The answer is 1 & 2

Hope this helps!

Papessa [141]3 years ago
4 0

Start out simple.

What are the multiples of 8?

The multiples of 8 would be:

1,2,4,8

What are the multiples of 10?

The multiples of 10 would be:

1,2,5,10

What are the multiplies of 12?

The multiples of 12 would be:

1,2,3,4,6,12

Now, go and circle the common numbers.

They would be:

1 and 2

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A ladder is leaning up against a 70 foot wall at an angle of elevation of 38° how far is the foot of the latter from the wall? R
SIZIF [17.4K]
Tanα=h/x

x=h/tanα

x=70/tan38 ft

x≈89.6 ft (to nearest tenth of a foot)

Note: the question seems strange, (because this would make the ladder almost 114 feet long!) or are we to assume as I did that the ladder is leaning against a point 70 feet high, or should if be a 70 foot ladder leaning against a wall of unknown height?

If it is just a 70 ft ladder at a 38° inclination the:

cosα=x/L

x=Lcosα

x=70cos38° ft

x≈55.2 ft
4 0
3 years ago
Triangle △ABC has an altitude CD . Which of the three points, A, B, D are between the other two if angles A and B are both acute
dolphi86 [110]
Hi!

Out of the three points D is between the other two acute angles if A and B are both acute.

Hope this helps!
4 0
2 years ago
Which rule describes the transformation that is a reflection across the x-acis
Alla [95]

Answer:

When you reflect a point across the line y = x, the x-coordinate and y-coordinate change places. If you reflect over the line y = -x, the x-coordinate and y-coordinate change places and are negated (the signs are changed). the line y = x is the point (y, x). the line y = -x is the point (-y, -x).

7 0
3 years ago
Which number produces a rational number when added to 1/5?
Ainat [17]

Answer:

The answer is -2/3.

8 0
3 years ago
Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?
azamat

Answer:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}

From the question, the center of the circle is located at (-6,2) and the radius is

r =  \sqrt{10}

We substitute the center and radius to get:

{(x -  - 6)}^{2}  +  {(y - 2)}^{2}  =  {( \sqrt{10} })^{2}

Simplify to obtain:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

7 0
2 years ago
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