What are the common multiples of 8,10,12?

Mathematics

2 answers:

timurjin [86]3 years ago

4 0

The answer is 1 & 2

Hope this helps!

Papessa [141]3 years ago

4 0

Start out simple.

What are the multiples of 8?

The multiples of 8 would be:

1,2,4,8

What are the multiples of 10?

The multiples of 10 would be:

1,2,5,10

What are the multiplies of 12?

The multiples of 12 would be:

1,2,3,4,6,12

Now, go and circle the common numbers.

They would be:

1 and 2

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BRAINLIEST AND FIVE STARS TO CORRECT ANSWER

Llana [10]

The answer is the first option, <-20, -42>.

We can find this by first finding what -2u would equal by multiplying <5, 6> by -2. This gives us <-10, -12>.

Then we need to find out what 5v is equal to, by multiplying <-2, -6> by 5 to get <-10, -30>.

Now that we know what -2u and 5v are, we can substitute them into the equation and get
<-10, -12> + <-10, -30>, which we can split up into -10 - 10 = -20, and -12 - 30 = -42, so your final answer is <-20, -42>.

I hope this helps!

8 0

3 years ago

Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.

nikitadnepr [17]

Answer:

The answer should be 45

Step-by-step explanation:

To get the whole are you would have to multiply the lenght with the Width and then take that answer and multiply it with the height

<u>BUT</u>

because you want the surface area, it would be just the lenght and width

15x3=45

so 45 is your answer.

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3 years ago

The minimum number of rigid transformations required to show that polygon ABCDE is congruent to polygon FGHIJ is 1 2 3 4 . A rot

MaRussiya [10]

I found the corresponding image. Pls. see attachment.

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