Answer:
hdudjhddhdjjdd
Step-by-step explanation:
djdjdbdhh
1. m1 = -9, m2 = 9
2. x1 = -10, x2 = 10
3. n1 = -3, n2= 3
4. x1 = -2, x2 =2
4 6 5 3 (from magician perspective)
3 5 6 4 (viewer perspective)
Detail:
From user perspective:
3 5 6 4 => 5 6 4 3 => 6 5 4 3
For magician perspective
3 4 5 6 (ascending order as)
Answer:
The number of different lab groups possible is 84.
Step-by-step explanation:
<u>Given</u>:
A class consists of 5 engineers and 4 non-engineers.
A lab groups of 3 are to be formed of these 9 students.
The problem can be solved using combinations.
Combinations is the number of ways to select <em>k</em> items from a group of <em>n</em> items without replacement. The order of the arrangement does not matter in combinations.
The combination of <em>k</em> items from <em>n</em> items is: 
Compute the number of different lab groups possible as follows:
The number of ways of selecting 3 students from 9 is = 

Thus, the number of different lab groups possible is 84.
Clue: The angle subtended at the centre of a circle is twice that subtended at its arc.