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CaHeK987 [17]
3 years ago
6

Please help I only need part b and part c​

Mathematics
1 answer:
IrinaVladis [17]3 years ago
5 0

Answer:

Here is the answer.

Step-by-step explanation:

b) students are the frequency. so we need to add all the frequency.

5 + 4  + 7 + 10 + 4=30 students

c) here we need to use the summation.

total/ frequency= mean

6*5=30

7*4=28

8*7=56

9*10=90

10*4=40

we need to add them all= 244

total frequency= 30

mean = 244/30= 8.133333333...≈ 8 (this is a rounded of value as  in 0.13, 3 goes on repeating.

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Which of the following is the same as 1.207 x 107?
melisa1 [442]

Answer:

C. Or the third option

Step-by-step explanation:

When you multiply something by a power of ten the decimal moves either left or right by the exponent. That probably sounds really confusing but here are some examples. If you multiply a number by 10^4 the decimal will move right 4 places making the number larger. Meanwhile if you multiplied it by 10^-4  it will move to the left 4 places making the number smaller. In your case, when you multiply 1.207 by 10^7, the decimal moves  places to the right which makes it 12,070,000

8 0
3 years ago
How can you decompose the composite figure to determine its area?
Anna007 [38]

For this case the first thing you should do is observe that the diameter of the four semicircles is the same.

Therefore, we can decompose the figure as follows:


1) We draw the diameters of the four semicircles to form a square.


2) We divide the figure into a square and four semicircles


3) The total area is the sum of the area of the square, plus the area of the 4 semicircles.


Answer:

c)as a square and four semicircles


5 0
3 years ago
Read 2 more answers
Select all possible values for x in the equation x^3=375?
Helga [31]
<h2>Hello!</h2>

The answers are:

The possible values for x in the equation, are:

First option, 5\sqrt[3]{3}

Second option,  \sqrt[3]{375}

<h2>Why?</h2>

To solve the problem, we need to remember the following properties of the exponents and roots:

a\sqrt[n]{b}=\sqrt[n]{a^{n}*b} \\\\\sqrt[n]{a^{m} }=a^{\frac{m}{n}}\\\\(a^{b})^{c}=a^{b*c}

Then, we are given the expression:

x^{3}=375

So, finding "x", we have:

x^{3}=375\\\\(x^{3})^{\frac{1}{3} } =(375)^{\frac{1}{3}}\\\\x=\sqrt[3]{375}=\sqrt[3]{125*3}=\sqrt[3]{125}*\sqrt[3]{3}=5\sqrt[3]{3}

Hence, the possible values for x in the equation, are:

First option, 5\sqrt[3]{3}

Second option,  \sqrt[3]{375}

Have a nice day!

7 0
3 years ago
Please help me idk this
Natali [406]

Answer:9000

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The 12th term of a sequence is 41 and the 15th term is 140. What is the nth term?
OLga [1]
An= mth term.
an=a₁+(n-1)*d

a₁₂=41
a₁₅=140

a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d 
a₁+11d=41    (1)

a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d 
a₁+14d=140    (2)

With the equiations (1) and (2)  build a system of equations
a₁+11d=41
a₁+14d=140

we solve it.
-(a₁+11d=41)
  a₁+14d=140
--------------------
       3d=99  ⇒d=99/3=33

a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322

an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n

an=-355+33n

To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
3 0
3 years ago
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