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CaHeK987 [17]
3 years ago
6

Please help I only need part b and part c​

Mathematics
1 answer:
IrinaVladis [17]3 years ago
5 0

Answer:

Here is the answer.

Step-by-step explanation:

b) students are the frequency. so we need to add all the frequency.

5 + 4  + 7 + 10 + 4=30 students

c) here we need to use the summation.

total/ frequency= mean

6*5=30

7*4=28

8*7=56

9*10=90

10*4=40

we need to add them all= 244

total frequency= 30

mean = 244/30= 8.133333333...≈ 8 (this is a rounded of value as  in 0.13, 3 goes on repeating.

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In an isosceles triangle the measure of the angle formed by two congruent sides is 80° what is the measure of each base triangle
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all the bases and sides are all each 80° then

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2 years ago
Zoe babysat for x+3 hours yesterday.she earned x-2 dollars per hour.write a polynomial expression that represents the amount Zoe
vekshin1

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y=3x+2

Step-by-step explanation:


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3 years ago
Michaela is training for a race. She runs 5 miles in 52 minutes. Her goal is to run 6 miles in 1 hour. By how many minutes per m
Leya [2.2K]

Answer:

2 min

Step-by-step explanation:

she runs 5 miles in 52 min

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2 years ago
F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)
Butoxors [25]

Answer:

The function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

Explanation:

Given the functions;

\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}

Solving for the function;

(g\circ f)(x)=g(f(x))

so, we have;

\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}

Therefore, the function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

5 0
1 year ago
The center of the inscribed circle of Triangle ABC is point , and the center of the circumscribed circle of Triagnle ABC is poin
quester [9]

Answer:

Part A: The center of The inscribed circle is the point S

Part B: The center of The circumscribed circle is the point P

Step-by-step explanation:

Part A: Find the center of The inscribed circle of ΔABC

The inscribed circle will touch each of the three sides of the triangle in exactly one point,

The center of the inscribed circle is the point of intersection between the angle bisectors of the triangle.

<u>So, </u>According to the previous definition:

A₁A₂ and B₁B₂ are the angle bisectors of ∠A and ∠B

So, the inter section between them is the center of <u>The inscribed circle</u>

<u>So, the center of The inscribed circle is the point S</u>

=====================================================

Part B: Find the center of The circumscribed circle of ΔABC

The circumscribed circle is the circle that passes through all three vertices of the triangle.

The center of the circumscribed circle is the point of intersection between the perpendicular bisectors of the sides.

<u>So,</u> According to the previous definition:

P₁P₂ and Q₁Q₂ are the perpendicular bisectors of AB and BC

So, the inter section between them is the center of <u>The circumscribed circle</u>

<u>So, the center of The circumscribed circle is the point P</u>

5 0
3 years ago
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