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4 years ago

What is the distance from home to school?

Mathematics

2 answers:

xxMikexx [17]4 years ago

8 0

The distance is 160ft!

liubo4ka [24]4 years ago

3 0

straight line from home to school =

sqrt(80^2 + 80^2) =

sqrt(12800) = 113.137 = 113.14 feet

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What is the simplified form of the expression

kirza4 [7]

1.First multiply 4(2y) and 4(6) which gives you (8y-24).
2.Then write out the whole problem: (15y-8y-24).
3.Subtract 15y-8y first since they have equal terms. That will give you 7y.
4.Now you have (7y-24).
Hoped this helps!!:-)))

6 0

3 years ago

Read 2 more answers

Proving lines parallel determine the value of X

Maslowich

when both l and m are parallel then 

(4x+7) = (6x-63)

-2x = -70

-x = -70/2

-x = -35

x = 35

hope it helps and ur day will full of happiness

3 0

3 years ago

50 POINTS

user100 [1]

$\huge \sf༆ Answer ༄$

According to the question ;

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y \propto x$

Now, let's add a constant of proportionality to replace proportionality sign with equal to :

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:y = kx$

[ where, k is proportionality constant ]

plug the value of x and y from any ordered pair in the table , for example : $\sf(\dfrac{1}{5} , 2)$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:2 = k \times \dfrac{1}{5}$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:k = 2 \times 5$

${ \qquad{ \sf{ \dashrightarrow}}} \: \: \sf \:k = 10$

Therefore, value of proportionality constant (k) is

$\overbrace{ \underbrace{\underline{ \boxed{ \sf 10 }}}}$

5 0

3 years ago

Stuck on this questions

Viktor [21]

Answer:

1. connotative 2. actually kicking a bucket

Step-by-step explanation:

1. Rugrat carries a negative connotation towards the child, and it's more associated with an unruly child rather than being an objective term talking about the child.

2. Denotative is literal so they are literally kicking a bucket.

3 0

3 years ago

WILL MARK BRAINLIEST!!! 40 POINTS!! ACTUAL ANSWERS, PLZZZ

steposvetlana [31]

Answer:

Part A:

$\left(x + 7\right)^{5}=x^{5} + 35 x^{4} + 490 x^{3} + 3430 x^{2} + 12005 x + 16807$

Part B:

The closure property describes cases when mathematical operations are CLOSED. It means that if you apply certain mathematical operations in a polynomial it will still be a polynomial. Polynomials are closed for sum, subtraction, and multiplication.

It means:

$\text{Sum of polynomials } \Rightarrow \text{ It will always be a polynomial}$

$\text{Subtraction of polynomials } \Rightarrow \text{ It will always be a polynomial}$

$\text{Multiplication of polynomials } \Rightarrow \text{ It will always be a polynomial}$

But when it is about division:

$\text{Division of polynomials } \Rightarrow \text{ It will not always/sometimes be a polynomial}$

Example of subtraction of polynomials:

$(2x^2+2x+3) - (x^2+5x+2)$

$x^2-3x+1$

Step-by-step explanation:

First, it is very important to define what is a polynomial in standard form:

It is when the terms are ordered from the highest degree to the lowest degree.

Therefore I can give:

$x^5-5x^4+3x^3-3x^2+7x+20$

but,

$x^5+3x^3-3x^2+7x+20-5x^4$ is not in standard form.

For this question, I can simply give the answer: $x^5-5x^4+3x^3-3x^2+7x+20$ and it is correct.

But I will create a fifth-degree polynomial using this formula

$(a+b)^n=\sum_{k=0}^n \binom{n}{k} a^{n-k} b^k$

Also, note that

$\binom{n}{k}=\frac{n!}{(n-k)!k!}$

For $a=x \text{ and } b=7$

$\left(x + 7\right)^{5}=\sum_{k=0}^{5} \binom{5}{k} \left(x\right)^{5-k} \left(7\right)^k$

$\text{Solving for } k \text{ values: } 0, 1, 2, 3, 4 \text{ and } 5$

Sorry but I will not type every step for each value of $k$

The first one is enough.

For $k=0$

$\binom{5}{0} \left(x\right)^{5-0} \left(7\right)^{0}=\frac{5!}{(5-0)! 0!}\left(x\right)^{5} \left(7\right)^{0}=\frac{5!}{5!} \cdot x^5= x^{5}$

Doing that for $k$ values:

$\left(x + 7\right)^{5}=x^{5} + 35 x^{4} + 490 x^{3} + 3430 x^{2} + 12005 x + 16807$

8 0

3 years ago