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suter [353]
3 years ago
6

Jeff is baking a cake. The recipe says that he has to mix 32 grams of vanilla powder to the flour. Jeff knows that 1 cup of that

particular vanilla powder has a mass of 128 grams. He added two over three of a cup of vanilla powder to the flour. Should Jeff add more vanilla powder to make the exact recipe or did he go over and by what amount?
Mathematics
2 answers:
kow [346]3 years ago
5 0

Answer:

Jeff has add more vanilla powder to  the exact recipe.

He had to start over again by only adding \frac{1}{4} cups of vanilla to the flour.

Step-by-step explanation:

1 cup of that particular vanilla powder has a mass of 128 grams

1 cup = 128 grams

Cups of vanilla added by Jeff = \frac{2}{3}

Mass of  \frac{2}{3} cups of vanilla :

\frac{2}{3}\times 128 grams=\frac{128}{3} grams=85.33 grams

Mass of vanilla required = 32 grams

Cups of vanilla required  =\frac{32}{128} =\frac{1}{4} cup

Jeff has already added 85.33 grams of vanilla which is greater the mass of 32 grams of vanilla. So, he had to start over again by only adding \frac{1}{4} cups of vanilla to the flour.

Naily [24]3 years ago
4 0
The situation above described that Jeff added two - thirds of 128 to the flour. The numerical value of (2/3)(128) is 85.33 grams. The recipe says to add only 32 grams of vanilla powder. Hence, Jeff went over the prescribed amount.

To determine the excess amount, subtract 32 from 85.33 which has a numerical value of 53.33 grams. 
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========================================================

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