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3 years ago

Explain how to subtract -7 - 6 as if you were teaching it to someone else.

Mathematics

1 answer:

Natasha_Volkova [10]3 years ago

4 0

Answer:

If you add a cold cube (add a negative number), the temperature goes down. If you remove a hot cube (subtract a positive number), the temperature goes down. And if you remove a cold cube (subtract a negative number), the temperature goes UP! That is, subtracting a negative is the same as adding a positive.

Step-by-step explanation:

thats the best way I think of at least

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Which description matches the graph of the inequality y > -X - 3?

Montano1993 [528]

Y is larger than minus x minus 3??

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3 years ago

Use cramer's rule of x-3y+z=13,3x+2y-z=1,5x+7y+2z=9

Lunna [17]

Answer:

uuyjj+jjh6688292837363627

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Step-by-step explanation:

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3 years ago

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The product of 9 and a number is 12 less than three times that number.<br><br> What is the number?

Murrr4er [49]

X - a number

$9x=3x-12|-3x\\ 6x=-12|:6\\
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$

8 0

3 years ago

Michael drives to work each day. He travels a total of 160 miles at the end of the work week. How far is Michael's house from wo

kobusy [5.1K]

Answer:

16 miles

Step-by-step explanation:

Assume the working day in a week is 5.

Given:

Michael drives 160 miles at the end of the work week. therefore as per assumption,

5 days of travelling distance = 160 miles

To find the distance of Micheal's house from work.

Solution:-

5 days of travelling distance = 160 miles --------------------(given)

Now,

Per day driving for work = $\frac{5\ days\ of\ travelling\ distance}{5}$

Per day driving for work = $\frac{160}{5}$

Per day driving for work = $32\ miles$

So, Micheal drives to work each day is 32 miles.

Therefore, the one side driving of Micheal is equal to distance of Micheal's house from work.

One side driving of Micheal = $\frac{Per\ day\ driving}{2}$

One side driving of Micheal = $\frac{32}{2}$

One side driving of Micheal = 16 miles

Therefore, the distance of Micheal's house from work is 16 miles.

4 0

3 years ago

HELP IM FAILING MATH OOOOFFFF

meriva

The point-slope form:

$y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points $(-4,\ -1)$ and $\left(\dfrac{1}{2},\ 3\right)$ .

Substitute:

$m=\dfrac{3-(-1)}{\frac{1}{2}-(-4)}=\dfrac{4}{4\frac{1}{2}}=\dfrac{4}{\frac{9}{2}}=4\cdot\dfrac{2}{9}=\dfrac{8}{9}\\\\y-(-1)=\dfrac{8}{9}(x-(-4))\\\\y+1=\dfrac{8}{9}(x+4)$

The standard form: Ax + By = C

$y+1=\dfrac{8}{9}(x+4)\qquad\text{multiply both sides by 9}\\\\9y+9=8(x+4)\qquad\text{use distributive property}\\\\9y+9=8x+32\qquad\text{subtract 9 from both sides}\\\\9y=8x+23\qquad\text{subtract 8x from both sides}\\\\-8x+9y=23\qquad\text{change the signs}\\\\\boxed{8x-9y=23}$

4 0

3 years ago