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nataly862011 [7]
4 years ago
6

The area of a rectangular piece of paper is 45 square inches. the perimeter is 28 inches. What are the dimensions of the paper?

Mathematics
2 answers:
Sophie [7]4 years ago
6 0
5 and 9, because 5X9= 45, and 5+5+9+9= 28
QveST [7]4 years ago
5 0
Area of a rectangle=base  x height
perimeter of a rectanble=2(base)+2(height)

base=x
height=y

we have to compute this system of equations:
xy=45
2x+2y=28

We solve this system by substitution method
xy=45  ⇒x=45/y

2(45/y)+2y=28
90/y + 2y=28
90+2y²=28y
2y²-28y+90=0
we divide each factor by "2" to simplify
y²-14y+45=0

We solve this quadratic equation:
y=[14⁺₋√(196-180)]/2
y=(14⁺₋4)/2
we have two solutions
y₁=9           ⇒x₁=45/9=5
y₂=5           ⇒x₂=45/5=9

Answer:  the dimensions fo the paper are 5 x 9


 
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Answer:

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3 0
3 years ago
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Can someone please help me in this question
Pie

Step-by-step explanation:

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f(-2) = 3(-2) - 2(-2)^2 = p

= -6 - 8

= -14

= p

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= 7.5 - 12.5

= -5

= q

b) graphing

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iii) the maximum occurs at

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4 0
3 years ago
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3 years ago
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b) f^{-1}(1)=2

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Given data:

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To find f(2), f^{-1}(1), f^{-1}(f(2))

Case a)

Now, substitute x = 2 in the equation 1 to find f (2)

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Case b)

Now, substitute x = 1 in the equation 2 to find  f^{-1}(1)

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