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2 years ago

How do i factor (10x^2-25x-15)

Mathematics

1 answer:

Otrada [13]2 years ago

4 0

5(2x^2 - 5x - 3) = 5(2x + 1)(x - 3)

hope this helps :)

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Boone fitnes sells gym passes in packs of 14. A competing gym, sells gym passes in sets of 20. If both sold the same number of p

sergeinik [125]

20: 20, 40, 60, 80, 100, 120, 140, 160, 180, 200

14: 14, 28, 42, 56, 70, 84, 98, 112, 126, 140

140 is the smallest number they have in common.

5 0

3 years ago

Which coordinate point(s) is a solution to the equation 3x + 2y =12?<br> (2,3),(-2,9),(3,2)

Leno4ka [110]

Answer:

points (2,3) and (-2,9)

Step-by-step explanation:

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3 years ago

The local street cart sells bacon egg and cheese sandwiches for $2.50, and soft drinks for $0.75. The street vendor made a total

zaharov [31]

Answer:

Step-by-step explanation:

3 0

2 years ago

A gas is said to be compressed adiabatically if there is no gain or loss of heat. When such a gas is diatomic (has two atoms per

Tems11 [23]

Answer:

The pressure is changing at $\frac{dP}{dt}=3.68$

Step-by-step explanation:

Suppose we have two quantities, which are connected to each other and both changing with time. A related rate problem is a problem in which we know the rate of change of one of the quantities and want to find the rate of change of the other quantity.

We know that the volume is decreasing at the rate of $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ and we want to find at what rate is the pressure changing.

The equation that model this situation is

$PV^{1.4}=k$

Differentiate both sides with respect to time t.

$\frac{d}{dt}(PV^{1.4})= \frac{d}{dt}k\\$

The Product rule tells us how to differentiate expressions that are the product of two other, more basic, expressions:

$\frac{d}{{dx}}\left( {f\left( x \right)g\left( x \right)} \right) = f\left( x \right)\frac{d}{{dx}}g\left( x \right) + \frac{d}{{dx}}f\left( x \right)g\left( x \right)$

Apply this rule to our expression we get

$V^{1.4}\cdot \frac{dP}{dt}+1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}=0$

Solve for $\frac{dP}{dt}$

$V^{1.4}\cdot \frac{dP}{dt}=-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}\\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot V^{0.4} \cdot \frac{dV}{dt}}{V^{1.4}} \\\\\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}$

when P = 23 kg/cm2, V = 35 cm3, and $\frac{dV}{dt}=-4 \:{\frac{cm^3}{min}}$ this becomes

$\frac{dP}{dt}=\frac{-1.4\cdot P \cdot \frac{dV}{dt}}{V}}\\\\\frac{dP}{dt}=\frac{-1.4\cdot 23 \cdot -4}{35}}\\\\\frac{dP}{dt}=3.68$

The pressure is changing at $\frac{dP}{dt}=3.68$ .

7 0

3 years ago

During the season, the Rangers played 25 games. They won 14 of the games.

34kurt

Answer:

See below

Step-by-step explanation:

Out of 25 games, they won 14

Fraction won = won / total = 14 / 25

Percent won = won /total * 100 % = 14/25 * 100 = .56 * 100 % = 56 %

To find the number of games lost

25-14 = 11

Fraction won = won / total = 11 / 25

Percent won = won /total * 100 % = 11/25 * 100 = .44 * 100 % = 44 %

To check your work, the percent total should be 100

56+44 = 100

5 0

1 year ago