Solve each system of equations. 2x + 3y = 3 3x + 5y = 6 o (4,1) Ob (0,1) (-3,3) Od (3-4)
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the numbers are 6 and 13
let x be one of the numbers then the other is 2x + 1
their sum increased by 7 = 26
x + 2x + 1 + 7 = 26
3x + 8 = 26
subtract 8 from both sides
3x = 26 - 8 = 18
divide both sides by 3
x = = 6
the numbers are 6 and (2 × 6) + 1 = 12 + 1 = 13