If a solution(s) exists y=y so we can say:
x^2-3x=-2x+2 add 2x to both sides
x^2-x=2 subtract 2 from both sides
x^2-x-2=0 factor
(x-2)(x+1)=0
So x=-1 and 2, using y=-2x+2 we find:
y(-1)=4 and y(2)=-2
So the two solutions occur at the points:
(-1,4) and (2,-2)
Answer:
20 lbs
Step-by-step explanation:
2/5ths of the food would be 20 pounds because:
2/5 * 50 = 20
2/10ths of the food would be 10 pounds because:
2/10 * 50 = 10
If we add those two together, we would get the total amount that the dog ate, which would be 30 pounds. SInce the dog ate 30 pounds of food out of the 50 pounds, there would be 20 pounds left in the bag at the end of two months:
50- ( 20+ 10) = 20
So,
0.2(n - 6) = 2.8
Distribute.
0.2n - 1.2 = 2.8
Add 1.2 to both sides.
0.2n = 4
Divide both sides by .2.
n = 20
Check.
0.2(20 - 6) = 2.8
Simplify inside parentheses.
0.2(14) = 2.8
Multiply.
2.8 = 2.8 This checks.
S = {2.8}
Answer: Our Cost function is discontinuous at every integer after x>10.
Step-by-step explanation:
Since we have given that
For the first 10 minutes , the service charges = $0.30
Let the number of additional minute be 't'.
Amount charge for each additional minute = $0.05
Using the greatest integer function:
So, Cost C of a call in terms of time 't' minutes would be
As we know that Greatest integer is discontinuous at every integer.
So, our Cost function is discontinuous at every integer after x>10.
