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3 years ago

A keyboard that costs $475 is marked down 15% for a sale. How much is the savings?

Mathematics

2 answers:

blondinia [14]3 years ago

8 0

Answer:71.25

Step-by-step explanation:

Bogdan [553]3 years ago

7 0

71.25 all you have to do its get $475 and multiply it by .15

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You are challenged to a lucky draw game. If you draw a face card (K, Q, J) from a standard deck of cards, you earn 10 points. If

Aleksandr [31]

The Expected value of a draw from the given question is; A; 0.77

We are told the face cards are K, Q, J. This means that there are 3 face cards for each of the 4 suits.

Since you earn 10 points for each face card, it means that;

total possible gain = 10 × 3 × 4 = 120

In a deck of cards, there are a total of 52 cards.

This means that;

Number of cards that are not K, Q or J = 52 - (4 × 3) = 40

Since 2 points are lost for drawing any of this 40 cards, then;

Total possible loss = 40 × 2 = 80

Expected gain = 120 - 80

Expected gain = 40

Expected value of a draw = 40/52

Expected value of a draw = 0.77

Read more about expected value at; brainly.com/question/1450915

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1 year ago

A rectangle has vertices at these coordinates.(3,6), (3,4), (6,4)What are the coordinates of the fourth vertex of the rectangle?

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3 years ago

Evaluate n + 5/5 When n= -10

vesna_86 [32]

Answer:

n + 5/5 = -9

Step-by-step explanation:

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2 years ago

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A debate team of 4 members for a high school will be chosen randomly from a potential group of 15 students. Ten of the 15 studen

iragen [17]

Answer:

A) 0.1538

Step-by-step explanation:

4 members are going to be chosen:

M1 - M2 - M3 - M4

We have to find the probability that for each member, one without experience is chosen. There is no replacents.

Initially, we have 15 students, of which 10 have none experience. So the probability that M1 is chosen as a student with no experience is $\frac{10}{15}$ .

Then, there are 14 students, of which 9 have no experience. So the probability that M2 is chosen as a student with no experience is $\frac{9}{14}$ .

For the third member, there are 13 students, of which 8 have no experience. So the probability that M3 is chosen as a student with no experience is $\frac{8}{13}$ .

For the last member, there are 12 students, of which 7 have no experience. So the probability that M4 is chosen as a student with no experience is $\frac{7}{12}$ .

What is the probability that none of the members chosen for the team have any competition experience?

This is

$P = \frac{10}{15}*\frac{9}{14}*\frac{8}{13}*\frac{7}{12} = 0.1538$

The correct answer is:

A) 0.1538

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2 years ago