64 has two square roots, namely 8 and −8 , since:
82=(−8)2=64.
When we say "the square root", what is usually intended is "the principal square root", which in the case of the Real square root of a positive number is the positive one. Any non-zero number n has two square roots.
Answer: The m ∡KLM is: 130° .
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Explanation:
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(3x − 4) = (4x − 27) ; (Since these are "bisected, congruent angles", they are equal).
⇒ 3x − 4 = 4x − 27 ;
⇒ Subtract "4x" from EACH SIDE of the equation; and add "4" to EACH SIDE of the equation;
⇒ 3x − 4 − 4x + 4 = 4x − 27 − 4x + 4 ;
to get:
⇒ - 1x = -23 ;
⇒ Divide EACH SIDE of the equation by "-1" ; to isolate "x" on one side of the equation; and to solve for "x" ;
⇒ -1x / -1 = -23 / -1 ; to get:
⇒ x = 23;
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To find m ∡KLM :
m ∡ KLM = (3x − 4) + (4x − 27) ;
{Note: Remember: (3x − 4) = (4x − 27) } ;
So, plug in our solved value for "x" ; which is: "x = 23" into one of the expressions for one of the congruent angles.
Let us start with: "(3x − 4)" .
(3x − 4) = 3x − 4 = 3(23) − 4 = 69 − 4 = 65 .
By plugging in our solve value for "x" ; which is: "x = 23" ; into the expression for the other congruent angle, we should get: "65" ;
Let us try:
(4x − 27) = 4x − 27 = 4(23) − 27 = 92 − 27 = 65. Yes!
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So to find m ∡KLM:
(3x − 4) + (4x − 27) = 65 + 65 = 130° .
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Alternate method:
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At the point which we have:
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To find m ∡KLM :
m ∡ KLM = (3x − 4) + (4x − 27) ; and at which we have our solved value for "x" ; which is: "x = 23" ;
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We can simply plug in our known value for "x" ; which is: "23" ; into the following:
m ∡ KLM = (3x − 4) + (4x − 27) = [(3*23) − 4] + [(4*23) − 27] ;
= (69 − 4) + (92 − 7) = 65 + 65 = 130° .
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{Note: Using this method, we determine that each angle is equal; that is, "65° ".}.
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