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Tema [17]
3 years ago
15

In the lab, Austin has two solutions that contain alcohol and is mixing them with each other. He uses 3 times as much Solution A

as Solution B. Solution A is 12% alcohol and Solution B is 20% alcohol. How many milliliters of Solution B does he use, if the resulting mixture has 244 milliliters of pure alcohol?
Mathematics
1 answer:
JulijaS [17]3 years ago
6 0

Austin uses 435.714 milliliters of solution B to get a resulting mixture that has 244 milliliters of pure alcohol.

Step-by-step explanation:

Step 1; Assume solution B has 1x ml of liquid in it. As solution A has three times that of solution B, it has 3x ml of liquid.

Step 2; In solution A there is 12% of alcohol and solution B has 20% alcohol. So alcohol content in solution A is 12% of 3x = 0.12 x 3x and the alcohol content in solution B is 20% of x= 0.20 x 1x.

Step 3; Use this formula

Concentration percent= \frac{(volume of solute)}{(volume of solution)} * 100

 here Volume of solute is the total of solution A and B= (0.12 x 3x) + (0.20 x 1x) which equals 0.56x. The volume of solution is 3x + 1x which equals 4x. Substituting numerator and denominators we get a volume of 14%.

Step 4;This 14% is the concentration of alcohol in the mixture of solution A and solution B which is given as 244 ml. If 14% is 244 ml then 100% equals 1742.857 milliliters. The total of solution A and B equal 4x which is 1742.857 milliliters. So we get solution A has 1307.1428 milliliters and solution B has 435.71428 milliliters of liquid.

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andrey2020 [161]

Adding and subtracting big polynomials like these are pretty easy. You just need to combine like terms. For example:

1.)

{5x}^{2}  +  {3x}^{2}  =  {8x}^{2}

2.)

({3x}^{2}  + 5xy) + (7xy + 2) =

{3x}^{2} + 12xy + 2

(The 3x^2 and the 2 stay intact while the 5xy and 7xy combine together)

All you have to do is combine the numbers that have the same powers of x and y with each other. x^2 will combine with x^2 and xy^2 wil combine with xy^2 exc. If there is no other number with the same x and y's, then you just leave it as it is in the answer.

Now with the original question, I see a -9xy^3, and thats gonna combine with the 3xy^3 in the second polynomial and the 2xy^3 in the third one.

- 9x {y}^{3}  + 3x {y}^{3}  + 2x {y}^{3} = \\  - 4x {y}^{3}

So far we have -4xy^3, the next term is going to be a -9x^4y^3, and that's gonna combine with the 3x^4y^3 in the third one.

- 9 {x}^{4} {y}^{3}  + 3 {x}^{4}  {y}^{3}  =  - 6{x}^{4}  {y}^{3}

We now finished adding the like terms that were in the first polynomial, we will move onto the second polynomial. The first term in this one is 3xy^3, in which we already added in the first step. At this point, it doesn't look like there are any other terms that have the same x and y behind them. So we can move on and write the final answer:

- 4x {y}^{3} - 6 {x}^{4} {y}^{3}  + 7 {y}^{4}  \\ - 8 {x}^{4} {y}^{4}

(All on the same line of course)

Also, for your second question, the order does not matter in which you write the terms. I could write the 7y^4 behind the -8x^4y^4 and it would still be the same answer.

If you have any other questions let me know :) while I double check my work.

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Simplify 138+15-2

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8 0
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sweet-ann [11.9K]
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3 years ago
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Stella [2.4K]

Answer:

\large\boxed{x=\dfrac{23}{33}}

Step-by-step explanation:

\text{Let}\ x=0.\overline{69}\\\\x=0.696969...\qquad\text{multiply both sides by 100}\\\\100x=69.696969...\qquad\text{subtract}\ x\ \text{from}\ 100x:\\\\100x-x=69.696969...-0.696969...\\\\99x=69\qquad\text{divide both sides by 99}\\\\x=\dfrac{69}{99}\\\\x=\dfrac{23}{33}

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3 years ago
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ivann1987 [24]

Answer:

Incorrect/No

Step-by-step explanation:

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<u>Follow the below guidelines:</u>

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Looking at the last one, we see that -2x-7=14, a positive number

Hope this helps!

--Applepi101

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