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d1i1m1o1n [39]
3 years ago
5

The piston diameter of a certain hand pump is 0.7 inch. The manager determines that the diameters are normally distributed, with

a mean of 0.7 inch and a standard deviation of 0.005 inch. After recalibrating the production machine, the manager randomly selects 28 pistons and determines that the standard deviation is 0.0044 inch. Is there significant evidence for the manager to conclude that the standard deviation has decreased at the a=0.05 level of significance?
What are the correct hypotheses for this test?

The null hypothesis is H0: p OR o OR u ---- less than OR does not equal OR equals OR greater than ---- 0.005 OR 0.0044

The alternative hypthosis is H1: (Choose one of the above choices)

Calculate the value of the test statistic.

Xsquared = (Round to three decimal places as needed).

The P-value is (Round to three decimal places as needed).

What is the correct conclusion at the a=0.05 level of significance?

Since the P-value is less OR greater than the level of significance, reject OR do not reject the null hypothesis. There is OR is not sufficient evidence to conclude that the standard deviation has decreased at the 0.05 level of significance.

Mathematics
1 answer:
podryga [215]3 years ago
8 0

Answer:

See explaination

Step-by-step explanation:

Please kindly check attachment for the step by step solution of the given problem.

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Angle 1 is vertical to Angle 2. Angle 1 =94, Angle 2 = 2(x-13), Find the value of x.
rodikova [14]

Answer:

x= 56

Step-by-step explanation:

86+94= 180 which if supplementary angles have to equal 180°

I don't know if you can tell but what's in red means distribute

then I added 26 on both sides with like terms

on the left side 86+26=112 and right side is left with 2x

then divide both sides by 2 to leave x by itself

112/2= 56 and 2x/2=x

so 56=x

4 0
2 years ago
If y has moment-generating function m(t) = e 6(e t −1) , what is p(|y − µ| ≤ 2σ)?
Lostsunrise [7]
Since \mathrm M_Y(t)=e^{6(e^t-1}, we know that Y follows a Poisson distribution with parameter \lambda=6.

Now assuming \mu,\sigma denote the mean and standard deviation of Y, respectively, then we know right away that \mu=6 and \sigma=\sqrt6.

So,

\mathbb P(|Y-\mu|\le2\sigma)=\mathbb P(6-2\sqrt6\le Y\le6+2\sqrt6)=\dfrac{66366}{175e^6}\approx0.940028
6 0
3 years ago
The Venn diagram above represents a university study about the correlation between playing video games and increased hand-eye co
Tanzania [10]
Region b represents kids with increased hand-eye coordination
3 0
3 years ago
I really need a good explanation on how to solve this, not just the answer please please please..
Alchen [17]

Answer:

Step-by-step explanation:

94

Mean = add all the numbers up and divide by how many numbers you added

So add (x +120  + 112 + 130 + 128 + 124 ) divided by 6  =118

x is the score you are looking for and 118 is the average he wants

so (x + 614 ) divided by 6 =118

now multiply both sides by 6

x + 614 = 118 times 6

x + 614 = 708

subtract 614 from both sides

x = 94

4 0
3 years ago
Which ordered pair would form a proportional relationship with the point graphed below?
Serhud [2]

40,20

hope this helps :)

6 0
3 years ago
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