If you have 205 students, and only 4 open positions, there would be multiple possibilities. For this question I would multiply 4 by 205, in which would contain every single possibility. 4 positions, 205 students, 4 times 205 would be 820 possibilities. Hope this helps.
Answer:
AROUND $0.20 per mile
Step-by-step explanation:
605/3052 is around 0.198, which rounds to 0.20.
These are in y=mx+b form where m=slope
sometimes b=0
vertical intercept means the y-intercept and the horizonatl intercept is the x intercept so the x intercept is when y=0 and the y intercept is when x=0 so the first one is
y=5x-15
slope=5
y-intercept=-15
x-intercept=3
y=7-x
this can be written as
y=-1x+7
slope=-1
y-intercept=7
x-intercept=7
4x=2y=12
we must get it into slope intercept form
divide the whole thing by 2x=y=12
we can disregard the 12 and get
2x=y or y=2x+0
slope=2
y-intercept=0
x-intercept=0
These are a huge pain. First set up your initial triangle with A and B as your base angles and C as your vertex angle. Now drop an altitude and call it h. You need to solve for h. Use sin 56 = h/13 to get that h = 10.8. The rule is that if the side length of a is greater than the height but less than the side length of b, you have 2 triangles. h<a<b --> 10.8<12<13. Those are true statements so we have 2 triangles. Side a is the side that swings, this is the one we "move", forming the second triangle. First we have to solve the first triangle using the Law of Sines, then we can solve the second.

to get that angle B is 64 degrees. Now find C: 180-56-64=60. And now for side c:

and c=12.5. That's your first triangle. In the second triangle, side a is the swinging side and that length doesn't change. Neither does the angle measure. Angle B has a supplement of 180-64 which is 116. So the new angle B in the second triangle is 116, but the length of b doesn't change, either. I'll show you how you know you're right about that in just a sec. The only angle AND side that both change are C and c. If our new triangle has angles 56 and 116, then C has to be 8 degrees. Using the Law of Sines again, we can solve for c:

and c = 2.0. We can look at this new triangle and determine the side measures are correct because the longest side will always be across from the largest angle, and the shortest side will always be across from the smallest angle. The new angle B is 116, which is across from the longest side of 13. These are hard. Ugh.