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s2008m [1.1K]
2 years ago
9

Use the graph of f to describe the transformation that results in the graph of g. f(x) = log x; g(x) = 2logx + 6 A.) The graph o

f g(x) is the graph of f(x) expanded vertically by a factor of 2, and translated 6 unit(s) up. B.) The graph of g(x) is the graph of f(x) reflected in the x-axis, expanded vertically by a factor of 2, and translated 6 unit(s) up. C.) The graph of g(x) is the graph of f(x) expanded vertically by a factor of 2, and translated 6 unit(s) down. D.) The graph of g(x) is the graph of f(x) reflected in the x-axis, expanded vertically by a factor of 2, and translated 6 unit(s) down.
Mathematics
1 answer:
Anastaziya [24]2 years ago
6 0

Answer:

  A.)  The graph of g(x) is the graph of f(x) expanded vertically by a factor of 2, and translated 6 unit(s) up.

Step-by-step explanation:

For vertical expansion by a scale factor of k, the graph of f(x) is transformed to ...

  g(x) = k·f(x)

For translation up by k units, f(x) is transformed to ...

  g(x) = f(x) +k

___

Comparing the following ...

  f(x) = log(x)

  g(x) = 2·log(x) +6

We see that a multiplication factor and an addition factor have been applied. That means ...

  g(x) is f(x) expanded vertically by a factor of 2, and translated up 6 units.

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AleksAgata [21]

Answer: Our required equation will be

y-80x=65

Step-by-step explanation:

Since we have given that

Number of days Max rented a motorbike at $465 = 5 days

Number of days Max rented a motorbike at $625 = 7 days

According to question, we'll use " Equation of line using two points "

(y-y_0)=\frac{y_2-y_1}{x_2-x_1}(x-x_0)\\\\(y-465)=\frac{625-465}{7-5}(x-5)\\\\(y-465)=80(x-5)\\\\y-465=80x-400\\\\y-80x=-400+465\\\\y-80x=65

Hence, our required equation will be

y-80x=65

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3 years ago
Find the variable of each ............
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Answer:

The answer is option d.

To find a we have to first find b

sin 60° = b / 10

b = 10 sin 60°

b = 5√3

sin 30° = b / a

b = 5√3

a = 5√3 sin 30°

a = 10√3

cos 30° = c / a

a = 10√3

c = 10√3 sin 30°

c = 15

cos 60° = d /10

d = 10 cos 60°

d = 5

a = 10√3 , b = 5√3 , c = 15 and d = 5

Hopethis helps.

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Answer:

If my calculations are correct.

Step-by-step explanation:

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A regulation basketball has a diameter of about 9 in. What is the best approximation for the volume of this ball? 3050 in³ 382 i
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The best apporximation for the volume of this ball is 382 cubic inches.

<h3>What is the volume of the ball?</h3>

The volume of the ball is calculated by the formula V = 4 / 3πr³. This formula is the same in the whole world.

Given

A regulation basketball has a diameter of about 9 in.

The radius of the ball is;

\rm Radius = \dfrac{Diameter}{2}\\\\Radius=\dfrac{9}{2}\\\\Radius=4.5\ inches

The volume of the ball is;

\rm Volume =\dfrac{4}{3}\pi r^3\\\\Volume=\dfrac{4}{3} \times 3.14 \times 4.5^3\\\\Volume =\dfrac{144.53}{3}\\\\Volume = 381.51\\\\Volume = 382 \ In^3 \ apporx

Hence, the best apporximation for the volume of this ball is 382 cubic inches.

To know more about volume click the link given below.

brainly.com/question/10647788

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