Express the number in scientific notation. 3.26

Precent of _____ -The ratio of a amount of decrease to the previous amount expressed as a percent

Bingel [31]

Answer:

Percent of decrease - the ratio of an amount of decrease to the previous amount expressed as a percent

Step-by-step explanation:

6 0

3 years ago

Adrian spends 35% of her paycheck on her bills. If her last check was for $927, how much did Adrian have left after paying her b

dlinn [17]

It would be 602.55 after all her bills are paid

5 0

3 years ago

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Carter drawers one side of equilateral triangle pqr on the coordinate plane at points P(-3, 2) and Q(5, 2). Which ordered pair i

Neko [114]

Given: Two coordinates of an equilateral triangle P(-3, 2) and Q(5, 2).

To find: Coordinate of third vertex R.

Solution: Let us take coordinate of R is (x,y).

Because we are given PQR is an equilateral triangle, all side of the triangle PQR are equal.

We can say PQ = QR = RS.

Let us find equations by using distance formula.

Distance between two coordinates is given by formula

$Distance = \sqrt{(x2-x1)^2+(y2-y1)^2}$

$PQ=\sqrt{(5-(-3))^2+(2-2)^2} = \sqrt{(5+3)^2+(0)^2} = \sqrt{8^2+0} = \sqrt{64} =8$

$QR=\sqrt{(x-5)^2+(y-2)^2} = \sqrt{x^2-10x+25 + y^2-4y+4} = \sqrt{x^2+y^2-10x-4y+29}$

$RS=\sqrt{(x-(-3)^2+(y-2)^2} = \sqrt{x^2+6x+9 + y^2-4y+4} = \sqrt{x^2+y^2+6x-4y+13}$ .

We know, PQ= QR and PQ= RS.

\sqrt{x^2+y^2-10x-4y+29}[/tex] = 8

Squaring both sides, we get

$x^2+y^2-10x-4y+29 =64$ -------- equation (1)

and \sqrt{x^2+y^2+6x-4y+13}[/tex] = 8

Squaring both sides, we get

$x^2+y^2+6x-4y+13=64$ ---------- equation (2).

Subtracting equation 2 from equation 1.

[/tex]x^2+y^2-10x-4y+29[/tex] = 64

[/tex]x^2+y^2+6x-4y+13[/tex] = 64

----------------------------------------------------

-16x +16 = 0

Subtracting 16 on both sides ,

-16x +16-16 = 0-16

-16x = -16

Dividing -16 on both sides.

-16x/-16 = -16/-16

x=1.

Plugging x=1 in first equation

$(1)^2+y^2-10(1)-4y+29 = 64$

$1+y^2-10-4y+29 = 64$ (Simplifying)

$y^2-4y+20 = 64$

Subtracting 64 from both sides.

$y^2-4y+20-64 = 64-64$

$y^2-4y-44 = 0$

By using quadratic formula..

$y=\frac{-(-4)+\sqrt{(-4)^2-4(1)(-44)} }{2(1)} and$

$y=\frac{-(-4)-\sqrt{(-4)^2-4(1)(-44)} }{2(1)} [tex]y=2\left(1+2\sqrt{3}\right),\:y=2\left(1-2\sqrt{3}\right)$

In decimal form

y=8.928, -4.928.

Therefore, coordinates of vertex R could be (1, 8.928) or (1, -4.928).

7 0

3 years ago

Help for just 100 points!

34kurt

The answer is C

the mean is the average which is solved by adding up all of the numbers and then dividing that by how many numbers there are, 45/5 = 9

6 0

2 years ago

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To support a local senior citizens center, a student club sent a flyer home to the n students in the school. The flyer said, "Pl

Licemer1 [7]

Answer:

the dollar amount the club would have if they reached half of their goal T + 50

the dollar amount the club would have if every student at the school donated 50 cents to the cause 0,5T

the dollar amount the club could donate if they made $50 more than their goal 0.25n

the dollar amount the club would still need to raise to reach its goal after every student at the school donated 50 cents 0.5n

the dollar amount the club would have if half of the students at the school each gave 50 cents T - 0.5n

Step-by-step explanation:

the dollar amount the club would have if they reached half of their goal T + 50

the dollar amount the club would have if every student at the school donated 50 cents to the cause 0,5T

the dollar amount the club could donate if they made $50 more than their goal 0.25n

the dollar amount the club would still need to raise to reach its goal after every student at the school donated 50 cents 0.5n

the dollar amount the club would have if half of the students at the school each gave 50 cents T - 0.5n

3 0

3 years ago