The answer is B
Hope it helps!!
In analytic geometry, using the common convention that the horizontal axis represents a variable x and the vertical axis represents a variable y, a y-intercept or vertical intercept is a point where the graph of a function or relation intersects the y-axis of the coordinate system. As such, these points satisfy x = 0.
Answer:
is the simplest form of given expression.
Step-by-step explanation:
The given question is 
To solve the problem we have to group or split middle term and then factorise

Taking
common from first two terms of denominator and 2 from next two terms

Now,taking x common from first two terms of numerator and -1 from next two terms and in denominator taking(x-1) common from both terms


Now cancel out x-1 from both numerator and denominator we get
is the required simplest form.
Answer mon
Step-by-step explanation:
Answer:
Same thing here Arc DE is also 100 degreese
cause the lines are connected to the center point.
Step-by-step explanation: