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3 years ago

Look at the Triangle below

Mathematics

1 answer:

MatroZZZ [7]3 years ago

3 0

Answer:

1. 44ft

2. 18ft

2. 396ft²

Step-by-step explanation:

1. Base

Sum of the total length

= 15ft + 29ft

= 44ft

Height.

The height is already given in the image above to be 18ft and it's runs perpendicular from the base.

Area

Formula for area of a triangle is 1/5(b)(h)

= 0.5 * 44 * 18

= 396 ft

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16x+2-0.1^2

Step-by-step explanation:

20x-0.1x^2-4x+2

16x+2-0.1x^2

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3 years ago

The width of a rectangle measures (s+5t) centimeters, and its length measures (s+2t)centimeters. Which expression represents the

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2 years ago

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At P-Town High School, the probability that a student takes Computer Programming and Spanish is 0.15. The probability that a stu

sp2606 [1]

Answer:

The probability that a student takes Spanish given that the student is taking Computer Programming = 0.375

Step-by-step explanation:

Given -

Let event A = student takes Spanish

Event B = student takes Computer Programming

$A \bigcap B$ = student takes Computer Programming and Spanish

P(B) = 0.4 , $P(A \bigcap B)$ = 0.15

What is the probability that a student takes Spanish given that the student is taking Computer Programming =

(Probability of an event occuring given that another event has already occured , we use condition probability )

$P(\frac{A}{B}) = \frac{P(A \bigcap B )}{P(B)}$

= $\frac{.15}{0.4}$

= 0.375

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3 years ago

Fifteen more than half a number is 9

Allisa [31]

15 more than half -12 = 9 or -6 + 15 = 9

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4 years ago

Find an equation of the tangent line to the hyperbola x2 a2 − y2 b2 = 1 at the point (x0, y0).

nalin [4]

The equation of the tangent line is $y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2} }{a^{2} y_{0} } + y_{0}$

To find the tangent to the hyperbola $\frac{x^{2} }{a^{2} } - \frac{y^{2} }{b^{2} }$ at (x₀, y₀), we differentiate the equation implicitly to find the equation of the tangent at (x₀, y₀).

So, $\frac{d}{dx} (\frac{x^{2} }{a^{2} } - \frac{y^{2} }{b^{2} }) = \frac{d0}{dx}\\\frac{d}{dx} \frac{x^{2} }{a^{2} } - \frac{d}{dx}\frac{y^{2} }{b^{2} }= 0\\\frac{2x }{a^{2} } - \frac{dy}{dx}\frac{2y }{b^{2} } = 0\\\frac{2x }{a^{2} } = \frac{dy}{dx}\frac{2y }{b^{2} } \\\frac{dy}{dx} = \frac{b^{2}x }{a^{2}y }$

So, at (x₀, y₀)

$\frac{dy}{dx} = \frac{b^{2} x_{0} }{a^{2} y_{0} }$

So, the equation of the tangent line is gotten from the standard equation of a line in point-slope form

So, $\frac{y - y_{0} }{x - x_{0} } = \frac{b^{2} x_{0} }{a^{2} y_{0} } \\y - y_{0} = \frac{b^{2} x_{0} }{a^{2} y_{0} }(x - x_{0}) \\y = \frac{b^{2} x_{0} }{a^{2} y_{0} }(x - x_{0}) + y_{0} \\y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2} }{a^{2} y_{0} } + y_{0}$

So, the equation of the tangent line is $y = \frac{b^{2} x_{0}x }{a^{2} y_{0} } - \frac{b^{2} x_{0}^{2} }{a^{2} y_{0} } + y_{0}$

Learn more about equation of tangent line here:

brainly.com/question/12561220

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3 years ago