Answer:
1- Positive correlation
2- Negative correlation
3- No correlation
Step-by-step explanation:
1- The more a player practices free throws, the better they will be at it and therefore will make more free throws. Thus, there is a positive correlation between the time spent practicing and the number of free throws made.
2- Since each item bought has a cost, the more items are bought, lower will be the checking account balance. Thus, there is a negative correlation the number of items bought and the checking account balance.
3- There is no explicit correlation between players heights and their ability to hit a baseball therefore it is fair to assume that there is no correlation between the height of baseball player and the number of hits made
for all of them its base times height
v=bh
1) (8*6/2)*9.5=228
2) (4.5/2)^2 *8= 40.5
3) (3.3* 8.3/2) *5.4= 74.0
4) ((3.2+4.8)/2)* 2.7 *4.4= 47.5
9514 1404 393
Answer:
3 months
Step-by-step explanation:
We don't know what's on your list of "useful financial formulas." One that can be used here is the formula for simple interest:
I = Prt . . . . . interest on principal P at annual rate r for t years
Solving for t gives ...
t = I/(Pr)
Filling in the given values, we can find t to be ...
t = 138/(4800×0.115) = 138/552 = 1/4
1/4 year is 3 months -- the duration of the loan.
First make 20 into a fraction, then solve; 3/5 · 20/1. 60/5 = 12. Hope that helps!
Step-by-step explanation:
Mean = 81740
Standard deviation = 4590
Sample size = 15
Alpha level = 1-0.95 = 0.05
Df = 15-1 = 14
Critical value:
alpha/2 = 0.05/2 = 0.05
t0.025
t critical value = 2.145
Margin of error ME
2.145 x 4590/√15
2.145 x 4590/3.873
ME = 2542.09
Confidence interval
Lower CI = mean - ME
= 81740-2542.09
= 79197.91
Upper CI = mean + ME
= 81740+2542.09
= 84282.09
[ 79197.91, 84282.09]
B.
Using excel, exact answer for CI
Lower limit = 79198.142724212173
Upper limit = 84281.8572757827
C.
The assumptions to be made from the population are that
1. Samples are random
2. These samples are gotten from an approximately normal distribution
