How many terms are there in the following expression: 3a+3ab+7b-4d?

Mathematics

2 answers:

Arada [10]3 years ago

5 0

Answer:

There are 4 terms.

Step-by-step explanation:

3ab

alexandr1967 [171]3 years ago

3 0

Answer:

Step-by-step explanation:

no need for 6AM and sons to know what u should be a good job of the first day and sons and peele is the only one who is the only person in this one who

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In 2009, a diabetic express company charged $38.85 for a vial of type A insulin and $30.34 for a vial of type B insulin. If a

Hoochie [10]

Answer:

The number of vials of type A insulin sold were _21__ and the number of vials of type B insulin sold were __29__.

Step-by-step explanation:

Let a = number of type A vials.

Let b = number of type B vials.

38.85a + 30.34b = 1695.71

a + b = 50

38.85a + 30.34b = 1695.71

(+) -38.85a - 38.85b = -1942.50

---------------------------------------------------

-8.51b = -246.79

b = 29

a + b = 50

a + 29 = 50

a = 21

Answer: The number of vials of type A insulin sold were _21__ and the number of vials of type B insulin sold were __29__.

6 0

3 years ago

Multiply (2x-5)(3x^2-4x+2)

fgiga [73]

Answer:

$\large\boxed{(2x-5)(3x^2-4x+2)=6x^3-23x^2+24x-10}$

Step-by-step explanation:

$\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(2x-5)(3x^2-4x+2)\\\\=(2x)(3x^2)+(2x)(-4x)+(2x)(2)+(-5)(3x^2)+(-5)(-4x)+(-5)(2)\\\\=6x^3-8x^2+4x-15x^2+20x-10\\\\\text{combine like terms}\\\\=6x^3+(-8x^2-15x^2)+(4x+20x)-10\\\\=6x^3-23x^2+24x-10$