Why is log of 1 with base b is 0

1 answer:

7 0

$De finition\ of\ logarithm:\log_ab=c\iff a^c=b\\where\ a > 0,\ a\neq1,\ b > 0\ and\ c\in\mathbb{R}\\\\therefore\\\\\log_b1=0\ because\ b^0=1\ for\ b > 0\ and\ b\neq1$

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